Answer:
legs limit the number of chairs that can be built
Step-by-step explanation:
The maximum number of chairs that can be built will be the minimum of the number of parts divided by the number of parts needed for each chair, as computed across the different kinds of parts required.
seats: 12 available, used 1 per chair: 12/1 = 12 chairs possible
backs: 15 available, used 1 per chair: 15/1 = 15 chairs possible
legs: 44 available, used 4 per chair: 44/4 = 11 chairs possible
The maximum number of chairs that can be built will be the minimum of 12, 15, and 11. That is, 11 chairs can be built, limited by the number of available legs.
X(30;0)
y(0;50)
substitue 0 for y and solve for x
substitute 0 in for x and solve for y
Answer:
The x represents the value of the point on the x axis or the horizontal line, and the y represents the vertical line. Now, lets solve for the first point. We can first see that it only moves to the left by two from zero, which is basically -2. So, right now we have (-2,y). We then look for the y in which we see that it is down -6 from zero, so it will be (-2,-6). Time to look for the second point. We should get (2,-3). Now, with these two points, it is time to find the slope intercept form.
Step-by-step explanation:
Answer:
a) 0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b) 0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.
Step-by-step explanation:
I am going to solve this question treating these events as Venn probabilities.
I am going to say that:
Event A: Person has type A blood.
Event B: Person has Rh- factor.
43% of people have type O blood
This means that 
15% of people have Rh- factor
This means that 
52% of people have type O or Rh- factor.
This means that 
a. Find the probability that a person has both type O blood and the Rh- factor.
This is
With what we have
0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b. Find the probability that a person does NOT have both type O blood and the Rh- factor.
1 - 0.06 = 0.94
0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.
