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Rudiy27
3 years ago
13

ARE THESE CORRECT?! PLS PLS PLS HELP ME IF THEY ARE WRONG LMK PLSSS

Mathematics
1 answer:
vazorg [7]3 years ago
6 0

Answer:

They seem correct!

Step-by-step explanation:

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How many athletes exercised more than 40 but less than 60 minutes
BaLLatris [955]
4.  When reading the stem and leaf plot the only values that fall between the range of  40 < x <60  is the 4 values of 45.  They are located at the tail end of the 4 stem after the zeros. The 40s and 60s are not counted because it is not mentioned equal to 40 or 60.
3 0
3 years ago
Read 2 more answers
What is 39 squared? A. 39 B. 1,482 C. 1,521 D. 78
iogann1982 [59]
Hey There!

The answer to you're question is C, because squared means to the power of two. So, 39 * 39 is 1,521.

Have A Brainly Day!
5 0
3 years ago
Suppose you pay a dollar to roll two dice. if you roll 5 or a 6 you Get your dollar back +2 more just like it the goal will be t
LiRa [457]

Answer:

(a)$67

(b)You are expected to win 56 Times

(c)You are expected to lose 44 Times

Step-by-step explanation:

The sample space for the event of rolling two dice is presented below

(1,1), (2,1), (3,1), (4,1), (5,1), (6,1)\\(1,2), (2,2), (3,2), (4,2), (5,2), (6,2)\\(1,3), (2,3), (3,3), (4,3), (5,3), (6,3)\\(1,4), (2,4), (3,4), (4,4), (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Total number of outcomes =36

The event of rolling a 5 or a 6 are:

(5,1), (6,1)\\ (5,2), (6,2)\\( (5,3), (6,3)\\ (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Number of outcomes =20

Therefore:

P(rolling a 5 or a 6)  =\dfrac{20}{36}

The probability distribution of this event is given as follows.

\left|\begin{array}{c|c|c}$Amount Won(x)&-\$1&\$2\\&\\P(x)&\dfrac{16}{36}&\dfrac{20}{36}\end{array}\right|

First, we determine the expected Value of this event.

Expected Value

=(-\$1\times \frac{16}{36})+ (\$2\times \frac{20}{36})\\=\$0.67

Therefore, if the game is played 100 times,

Expected Profit =$0.67 X 100 =$67

If you play the game 100 times, you can expect to win $67.

(b)

Probability of Winning  =\dfrac{20}{36}

If the game is played 100 times

Number of times expected to win

=\dfrac{20}{36} \times 100\\=56$ times

Therefore, number of times expected to loose

= 100-56

=44 times

8 0
3 years ago
What 12/12+12/12+8/12=
Fudgin [204]

Answer:

8/3

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
The product of -8 and x is -96.
velikii [3]
-96 divided by -8 = 12
Negative and negative make a positive, therefore the x has to be a positive for the answer to be a negative (-96)
Since you're looking for the product, you divide the two numbers you have.
3 0
3 years ago
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