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2 years ago

Given the image below, , , are perpendicular bisectors of △.

Mathematics

1 answer:

Neko [114]2 years ago

8 0

Answer:

just want

Step-by-step explanation:

the points are great

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Solve. 8+2=16106. 5+4=2091. 9+6=54153. 7+5=35122. 20+3=602317. 30+1=303129. 18+4=722214. 10+5=??

Sergio [31]

answer:

505155

step-by-step explanation:

multiply, add, and subtract the first two numbers of the equation in that order to get the final number

8 + 2 = 16106: 8 x 2 = 16, 8 + 2 = 10, 8 - 2 = 6 to get the number 16106

5 + 4 = 2091: 5 x 4 = 20, 5 + 4 = 9, and 5 - 4 = 1 to get the number 2091

9 + 6 = 54153: 9 x 6 = 54, 9 + 6 = 15, and 9 - 6 = 3 to get the number 54153

7 + 5 = 35122: 7 x 5 = 35, 7 + 5 = 12, and 7 - 5 = 2 to get the number 35122

20 + 3 = 602317: 20 x 3 = 60, 20 + 3 = 23, and 20 - 3 = 17 to get the number 602317

30 + 1 = 303129: 30 x 1 = 30, 30 + 1 = 31, and 30 - 1 = 29 to get the number 303129

18 + 4 = 722214: 18 x 4 = 72, 18 + 4 = 22, and 18 - 4 = 14 to get the number 722214

10 + 5 = 505155: 10 x 5 = 50, 10 + 5 = 15, and 10 - 5 = 5 to get the number 505155

6 0

3 years ago

Please help! answer each column (question in picture) for brainliest

Inga [223]

Answer:

See attachment

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

F(x)=1/2×+6 plz helpppppppppp

FromTheMoon [43]

Answer:

The solution set can be given as:

$\{x|x\ \epsilon\ R,x\neq -3\}$

Step-by-step explanation:

Given function:

$f(x)=\frac{1}{2x+6}$

To find the domain of the function in set notation.

Solution:

For the function $f(x)$ to exist the denominator must be ≠ 0

We have the denominator $(2x+6)$ which cannot be = 0.

Thus, we can find the domain of the function using the above relation.

The function $f(x)$ will not exist when:

$2x+6=0$

Solving for $x$

Subtracting both sides by 6.

$2x+6-6=0-6$

$2x=-6$

Dividing both sides by 2.

$\frac{2x}{2}=\frac{-6}{2}$

∴ $x=-3$

Thus, the function will not exist at $x=-3$ . This means it has all real number solutions except -3.

The solution set can be given as:

$\{x|x\ \epsilon\ R,x\neq -3\}$

3 0

3 years ago

MathsWatch Question<br> Please Help

seraphim [82]

Make sure you make me brainest

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2 years ago

Help help help help help

QveST [7]

Answer:

Step-by-step explanation:

Let me know if anything is unclear :)

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2 years ago