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soldier1979 [14.2K]
3 years ago
13

Does paint and cardboard have joints in it

Physics
1 answer:
Inessa05 [86]3 years ago
7 0
Noooo it doesn’t because it’s not apart of the body
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CAN SOMEONE PLEASE ANSWER NUMBER 10 FOR ME WITH AN EXPLANATION HURRY I HAVE LIMITED TIME PLEASE!!!
lara31 [8.8K]
Answer: B

EXPLANATION: the volume and temperature of the gas are directly proportional hence an increase in volume would lead to an increase in temperature and vice versa
4 0
3 years ago
Why is g called the universal gravitational constant<br>​
guapka [62]

Explanation:

Hey there!

<em>Universal gravitation constant (g) is the force of gravitation produced between two bodies of unit mass each separated by unit distance between their centers. The value of universal gravitation constant (g) is 6.67 Nm²/kg², which is constant all over the world. So, that's why it is called universal gravitation </em><em>constant.</em>

<em><u>Hope</u></em><em><u> it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

5 0
3 years ago
Two long, parallel wires are separated by a distance of 3.80 cm . The force per unit length that each wire exerts on the other i
IgorLugansk [536]

Answer:

(a). I' = 17.24 A

(b).The current in second wire is in opposite direction compare to first wire.

Explanation:

Given data

r = 0.038 m

\frac{F}{L} = 4.9 × 10^{-5} \frac{N}{m}

I = 0.54 A

(a). The current in the second wire is calculated as

I'=\frac{F}{L} \frac{2 \pi r}{\mu I}

Put all the values in above formula we get

I' = \frac{ (2) (3.14) (0.038)}{4 \pi (0.54)} 490

I' = 17.24 A

(b). The current in the two wires is in opposite directions because the wires repeal each other. therefore the current in second wire is in opposite direction compare to first wire.

7 0
4 years ago
n isolated charged soap bubble of radius R0=7.45 cmR0=7.45 cm is at a potential of V0=307.0 volts.V0=307.0 volts. If the bubble
Gnesinka [82]

Complete Question

An isolated charged soap bubble of radius R0 = 7.45 cm  is at a potential of V0=307.0 volts. V0=307.0 volts. If the bubble shrinks to a radius that is 19.0%19.0% of the initial radius, by how much does its electrostatic potential energy ????U change? Assume that the charge on the bubble is spread evenly over the surface, and that the total charge on the bubble r

Answer:

The difference is    U_f -U_i = 16 *10^{-7} J

Explanation:

From the question we are told that

     The radius of the soap bubble  is  R_o =  7.45 \ cm =  \frac{7.45}{100} =  0.0745 \ m

      The potential of the soap bubble is  V_1  =307.0 V

      The new radius of the soap bubble  is R_1 =  0.19 * 7.45=1.4155\ cm = 0.014155 \ m

The initial electric potential is mathematically represented as

     U_i  = \frac{V_1^2 R_o }{2k }

The final  electric potential is mathematically represented as

    U_f  = \frac{V_2^2 R_1 }{2k }

The initial potential is mathematically represented as

     V_1 =  \frac{kQ}{R_o}

The final  potential is mathematically represented as

        V_2 =  \frac{kQ}{R_1}

Now  

         \frac{V_2}{V_1}  =  \frac{R_o}{R_1}

substituting values

        \frac{V_2}{V_1}  =  \frac{7.45}{1.4155} =   \frac{1}{0.19}

=>      V_2 =  \frac{V_1}{0.19}

    So

         U_f  = \frac{V_1^2 R_2 }{2k * 0.19^2}

Therefore

        U_f -U_i = \frac{V_1^2 R_2 }{2k * 0.19^2} - \frac{V_1^2 R_o }{2k }

       U_f -U_i =     \frac{V_1^2}{2k} [\frac{ R_1 }{ * 0.19^2} - R_o]

where k is the coulomb's constant with value 9*10^{9} \  kg\cdot m^3\cdot s^{-4}\cdot A^2.

substituting values

       U_f -U_i =     \frac{307^2}{9 * 10^{9}} [\frac{ 0.014155 }{ 0.19^2} - 0.0745]

       U_f -U_i = 16 *10^{-7} J

           

     

8 0
3 years ago
What pattern is seen on the moon from earth?
igomit [66]

If you mean pattern designs it’s rocky bumpy and you can see the circle patterns

If you mean phases the here’s a picture

7 0
3 years ago
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