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alexdok [17]
3 years ago
10

The gravitational force between the Sun (mass -1.99 1030 kg) and Mercury (mass 3.30 x 1023 kg) is 899 1021 N. How far is Mercury

from the Sun?
Physics
2 answers:
Daniel [21]3 years ago
7 0
The gravitational force between the two objects is given by:
F=G  \frac{m_1 m_2}{d^2}
where
G=8.99 \cdot 10^{-11} m^3 kg^{-1} s^{-2} is the gravitational constant
m_1 = 1.99 \cdot 10^{30} kg is the Sun mass
m_2 = 3.30 \cdot 10^{23} kg is the mass of Mercury
and d is the distance between Sun and Mercury. Since we know the force:
F=8.99 \cdot 10^{21} N
we can re-arrange the formula to find d:
d= \sqrt{ G \frac{m_1 m_2}{F} }=6.98 \cdot 10^{10}m
balandron [24]3 years ago
5 0

Answer:

B - 6.98 x 10^7 km

Explanation:

took it on egde

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Lerok [7]
Assuming the gas behaves ideally,
PV/T = constant. P will also be constant in this giving us:
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3 years ago
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Four solid plastic cylinders all have radius 2.41 cm and length 5.94 cm. Find the charge of each cylinder given the following ad
Paladinen [302]

Answer:

Check explanation

Explanation:

QUICK NOTE: THE QUESTION IS NOT COMPLETE. Although it is not, we can make assumptions, since we only need values for the UNIFORM CHARGE DENSITY.

SO, LET US BEGIN;

To solve this question we are to use the equation (1) below;

Charge,Q = uniform charge density,p × Total area of the cylinder,A ------------------------------------------------------------------------(1).

From the question, we are given radius, R to be 2.41 cm and length, L to be 5.94 cm.

Step one: calculate for the total area of the cylinder, A.

Total area of the cylinder, A= area of the top surface + area of the buttom + area of the curved surface of the cylinder.

Hence, total area of the cylinder,A is;

==> πR^2 + πR^2 + 2πRL. -------------------------------------------------------------------------(2).

Then, total area of the cylinder,A is;

==> (L + R)2πR.

Step two: find the charge of each cylinder.

===> For the first cylinder; we have the uniform charge density to be 35 nC/m^2.

Therefore, the combination of equation (1) and (3) gives;

Charge Q= p × (L + R)2πR...----------------------------(4)

Hence, Q= 35 × [(5.94 + 2.41) 2× 3.143 × 5.94].= 10912.615 coulumb.

====> For the second cylinder, we have a uniform charge density of 50 nC/m^2.

Using equation (4), charge,Q= 15,589.45 Coulumb

=====> For THE third cylinder, the uniform charge density is 600, we make use of equation (4);

Charge,Q= 600×311.789.

Charge,Q= 187,073.4 coulumb.

====> For THE fourth cylinder, the uniform charge density is 750 nC/m^2.., we make use of equation (4);

Charge,Q= 233,841.75 coulumb.

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3 years ago
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<span>Very High Mass: Run through their fuel exceedingly fast. *Die* relatively quickly (in the range of tens to hundreds of millions of years instead of billions and beyond) and go out with style, Supernova that will leave behind a neutron star (the *kind of very high mass stars" end this way) or a black hole (the *very very high mass stars* end this way.)</span>
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Answer:

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Explanation:

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From the information given in question we have

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8 0
3 years ago
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yaroslaw [1]

Answer:

<em>Hewo Otaku Kun Here! (UwU)</em>

Explanation:

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2. Tree branches high up in a tree have potential energy because they can fall to the ground.

3. A stick of dynamite has chemical potential energy that would be released when the activation energy from the fuse comes into contact with the chemicals.

4. The food we eat has chemical potential energy because as our body digests it, it provides us with energy for basic metabolism.

5. A stretched spring in a pinball machine has elastic potential energy and can move the steel ball when released.

6. When a crane swings a wrecking ball up to a certain height, it gains more potential energy and has the ability to crash through buildings.

7. A set of double "A" batteries in a remote control car possess chemical potential energy which can supply electricity to run the car.

<em>happy to help!</em>

<em>from: Otaku Kun ^^</em>

8 0
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