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alexdok [17]
3 years ago
10

The gravitational force between the Sun (mass -1.99 1030 kg) and Mercury (mass 3.30 x 1023 kg) is 899 1021 N. How far is Mercury

from the Sun?
Physics
2 answers:
Daniel [21]3 years ago
7 0
The gravitational force between the two objects is given by:
F=G  \frac{m_1 m_2}{d^2}
where
G=8.99 \cdot 10^{-11} m^3 kg^{-1} s^{-2} is the gravitational constant
m_1 = 1.99 \cdot 10^{30} kg is the Sun mass
m_2 = 3.30 \cdot 10^{23} kg is the mass of Mercury
and d is the distance between Sun and Mercury. Since we know the force:
F=8.99 \cdot 10^{21} N
we can re-arrange the formula to find d:
d= \sqrt{ G \frac{m_1 m_2}{F} }=6.98 \cdot 10^{10}m
balandron [24]3 years ago
5 0

Answer:

B - 6.98 x 10^7 km

Explanation:

took it on egde

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A distant planet with a mass of (7.2000x10^26) has a moon with a mass of (5.0000x10^23). The distance between the planet and the
BARSIC [14]

Answer:

Explanation:

This is a simple gravitational force problem using the equation:

F_g=\frac{Gm_1m_2}{r^2} where F is the gravitational force, G is the universal gravitational constant, the m's are the masses of the2 objects, and r is the distance between the centers of the masses. I am going to state G to 3 sig fig's so that is the number of sig fig's we will have in our answer. If we are solving for the gravitational force, we can fill in everything else where it goes. Keep in mind that I am NOT rounding until the very end, even when I show some simplification before the final answer.

Filling in:

F_g=\frac{(6.67*19^{-11})(7.2000*10^{26})(5.0000*10^{23})}{(6.10*10^{11})^2} I'm going to do the math on the top and then on the bottom and divide at the end.

F_g=\frac{2.4012*10^{40}}{3.721*10^{23}} and now when I divide I will express my answer to the correct number of sig dig's:

Fg= 6.45 × 10¹⁶ N

8 0
3 years ago
Which of Newton's motion laws BEST explains WHY a rock falls when it is dropped from a bridge?
erma4kov [3.2K]
It’s A because it stays in motion whenever you drop it
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A cart rolling at ground level has K = 1500 J. It comes to a ramp, rolls up the ramp to an elevated platform. When it's on this
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8 0
3 years ago
How long must a simple pendulum be if it is to make exactly one swing per four seconds? (That is, one complete oscillation takes
cricket20 [7]

Answer:

Length of the pendulum will be 3.987 m

Explanation:

We have given time period of the pendulum T = 8 sec

Acceleration due to gravity g=9.81m/sec^2

We have to find the length of the simple pendulum

We know that time period of the simple pendulum is given by

T=2\pi \sqrt{\frac{l}{g}}

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3 0
3 years ago
How will the amount of power change if less work is done in more time?
yKpoI14uk [10]

The amount of power change if less work is done in more time"then the amount of power will decrease".

<u>Option: B</u>

<u>Explanation:</u>

The rate of performing any work or activity by transferring amount of energy per unit time is understood as power. The unit of power is watt

Power = \frac{Work}{Time}  

Here this equation showcase that power is directly proportional to the work but dependent upon time as time is inversely proportional to the power i.e as time increases power decreases and vice versa.

This can be understood from an instance, on moving a load up a flight of stairs, the similar amount of work is done, no matter how heavy but  when the work is done in a shorter period of time more power is required.

7 0
3 years ago
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