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1 year ago

HELP!! IM VERY CONFUSED ON HOW TO DO THIS!!

Mathematics

2 answers:

Maksim231197 [3]1 year ago

7 0

Answer:
Length side of triangle: 9 Inches
Length side of hexagon: 4.5 Inches

Explanation:

Triangle - 3 sides
1 side= (1.4x + 2 inches)

Hexagon - 6 sides
1 side= (0.5x + 2 inches)

Total perimeter of triangle = 3(1.4x + 2 inches) = 4.2x + 6 inches

Total perimeter of hexagon = 6(0.5x + 2 inches) = 3x + 12 inches

4.2x + 6 inches = 3x + 12 inches
4.2x - 3x = 12 inches - 6 inches
1.2x = 6 inches
0.1x = 0.5 inches

Side length of triangle =
0.5x = 2.5 inches
2.5 inches + 2 inches = 4.5 inches

Side length of hexagon =
1.4x = 7 inches
7 inches + 2 inches = 9 inches

dusya [7]1 year ago

6 0

Answer:

The side length of the equilateral triangle 9 inches.

The side length of the hexagon 4.5 inches.

The side length of the equilateral triangle = 1.4x + 2

So, the perimeter = 3(1.4x + 2) = 4.2x + 6.

The side length of the hexagon = 0.5x + 2

So, the perimeter = 6(0.5x + 2) = 3x + 12.

Given the the perimeters are equal.

So,

Hence,

The side length of the equilateral triangle = 1.4x + 2 = 1.4(5) + 2 = 9

The side length of the hexagon = 0.5x + 2 = 0.5(5) + 2 = 4.5

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Can someone help me find the equivalent expressions to the picture below? I’m having trouble

miss Akunina [59]

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is $\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$ .

Now we will solve this expression with the help of law of exponents.

$\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}$

$=2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}$

$=2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}$

$=2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}$

$=2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }$ [Option 2]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$ [Option 1]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$

$=(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }$

$=\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} }$ [Option 3]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }$

$=\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}}$ [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

6 0

2 years ago

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Luden [163]

Answer:

£270

Step-by-step explanation:

Works 7.5 hours per shift and there are 5 shifts in a week, hence

hours worked per week = 7.5 × 5 = 37.5

Pay per hour = £7.20, thus

Earnings for a week = 37.5 × 7.20 = £270

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2 years ago

Marcus needs to rewrite f(x) = x2 + 6x + 4 in vertex form.

irakobra [83]

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4 0

3 years ago

Read 2 more answers

Use the distributive property to express 15+45

Nuetrik [128]

Answer:
15(1+3)

Explanation:
The distributive property can be generally expressed as follows:
ab + ac = a(b+c)

The given expression is:
15 + 45

We know that:
15 = 1*15
45 = 3*15

Therefore, the given expression can be written as:
1*15 + 3*15

Taking 15 as a common factor and applying the above rule, we will reach the following expression:
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Hope this helps :)

5 0

3 years ago

The time you have before finance charges are assessed is called the a. credit limit. c. APR. b. incentive. d. grace period.

Tanya [424]

Answer:

The time you have before finance charges are assessed is called the Grace period

option-D

Step-by-step explanation:

we know that

Grace period is the extra time given to customer to pay amount before finance charges

But once grace period passes , customer will have to pay extra fee or penalty with interest with passing days

So,

The time you have before finance charges are assessed is called the Grace period

So,

option-D

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3 years ago