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Ksenya-84 [330]
3 years ago
15

What other information do you need to prove triangle INF=CAT by the ASA Postulate?

Mathematics
1 answer:
tekilochka [14]3 years ago
7 0
Label the angles on the given figure an x and y and label the unknown angles as z (see the figure below).
Because the sum of angles in a triangle = 180°, angle z is correct for all three triangles.

In order to prove that ΔINF = ΔCAT by the ASA Postulate, 
1.  We should show that AC = IN, or
2. We should show that AT = NF.
Proving either of the two options means that we have congruent isosceles triangles.

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Lapatulllka [165]
Could you show a picture so i could understand a little bit better?
6 0
2 years ago
BC<br> Round your answer to the nearest hundredth.<br> А<br> 50°<br> ?<br> 3<br> B
emmasim [6.3K]

Use the sine function.

sine = opposite side of triangle divided by the hypotenuse.

Here is the set up:

sin(50°) = BC/3

sin(50°)/3 = BC

Use your calculator to simply left side.

Take it from here.

6 0
3 years ago
Read 2 more answers
Jack is at the zoo looking up at a monkey
sasho [114]

The height of the pole at which the monkey is at the top is 10.2 feet.

<h3>Trigonometric ratio</h3>

Trigonometric ratio is used to show the relationship between the angles and sides of a right angled triangle.

Let h represent the height of the pole, hence using trigonometric ratio:

tan(23) = h/24

h = 10.2 feet

The height of the pole at which the monkey is at the top is 10.2 feet.

Find out more on Trigonometric ratio at: brainly.com/question/4326804

4 0
2 years ago
I need help before tomorrow
Hitman42 [59]

Hello from MrBillDoesMath!

Answer:

The equations "are balanced"


Discussion:

Given that

4 + 4 = 8                 => subtracting k from both sides

4 + 4 - k = 8 -k


so the equation shown IS correct. The answer should be the equations "are balanced"


Thank you,

MrB

8 0
3 years ago
If a scalene triangle has its measures 4 m, 11 m and 8 m, find the largest angle.
soldier1979 [14.2K]

Answer:

129.8 approximately

Step-by-step explanation:

So this sounds like a problem for the Law of Cosines. The largest angle is always opposite the largest side in a triangle.

So 11 is the largest side so the angle opposite to it is what we are trying to find. Let's call that angle, X.

My math is case sensitive.

X is the angle opposite to the side x.

Law of cosines formula is:

x^2=a^2+b^2-2ab \cos(X)

So we are looking for X.

We know x=11, a=4, and b=8 (it didn't matter if you called b=4 and a=8).

11^2=4^2+8^2-2(4)(8)\cos(X)

121=16+64-64\cos(X)

121=80-64\cos(X)

Subtract 80 on both sides:

121-80=-64\cos(X)

41=-64\cos(X)

Divide both sides by -64:

\frac{41}{-64}=\cos(X)

Now do the inverse of cosine of both sides or just arccos( )

[these are same thing]

\arccos(\frac{-41}{64})=X

Time for the calculator:

X=129.8 approximately

3 0
4 years ago
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