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Ksenya-84 [330]
3 years ago
15

What other information do you need to prove triangle INF=CAT by the ASA Postulate?

Mathematics
1 answer:
tekilochka [14]3 years ago
7 0
Label the angles on the given figure an x and y and label the unknown angles as z (see the figure below).
Because the sum of angles in a triangle = 180°, angle z is correct for all three triangles.

In order to prove that ΔINF = ΔCAT by the ASA Postulate, 
1.  We should show that AC = IN, or
2. We should show that AT = NF.
Proving either of the two options means that we have congruent isosceles triangles.

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What is an equation of the line that passes through the point ( 6 , − 2 ) (6,−2) and is perpendicular to the line 6 x + y = 2 6x
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Answer:

An equation of the line that passes through the point (6, − 2) and is perpendicular to the line will be:

  • y=\frac{1}{6}x-3

Step-by-step explanation:

We know that the slope-intercept form of the line equation is

y=mx+b

where m is the slope and b is the y-intercept.

Given the line

6x+y=2

Simplifying the equation to write into the  slope-intercept form

y = -6x+2

So, the slope = -6

As we know that the slope of the perpendicular line is basically the negative reciprocal of the slope of the line.

Thus, the slope of the perpendicular line will be: -1/-6 = 1/6

Therefore, an equation of the line that passes through the point (6, − 2) and is perpendicular to the line will be

y-y_1=m\left(x-x_1\right)

substituting the values m = 1/6 and the point (6, -2)

y-\left(-2\right)=\frac{1}{6}\left(x-6\right)

y+2=\frac{1}{6}\left(x-6\right)

subtract 2 from both sides

y+2-2=\frac{1}{6}\left(x-6\right)-2

y=\frac{1}{6}x-3

Therefore, an equation of the line that passes through the point (6, − 2) and is perpendicular to the line will be:

  • y=\frac{1}{6}x-3
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