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Nonamiya [84]
3 years ago
6

HELP NOW PLEASE!

Mathematics
2 answers:
tekilochka [14]3 years ago
6 0
It should be C. 1/3
Leokris [45]3 years ago
5 0

Answer:

-3/1 is the correct answer

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Arc cd located on circle a has a central angle of 135 the radius is the circle is 24 centimeters what is the length of arc cd
kherson [118]

\textit{arc's length}\\\\ s = \cfrac{\theta \pi r}{180}~~ \begin{cases} r=radius\\ \theta =\stackrel{degrees}{angle}\\[-0.5em] \hrulefill\\ r=24\\ \theta =135 \end{cases}\implies s=\cfrac{(135)\pi (24)}{180}\implies s=18\pi ~cm

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2 years ago
You purchased 8 pounds 10 ounces of candy shop you want to split it equally among 3 classrooms at a local school. How much shoul
amid [387]
<span>Given than 1 pound = 16 ounces, we have a total of 8*16 + 10 = 138 ounces which we must devide among the 3 classrooms. This gives us 138/3 = 46 ounces per classroom, or 2 pounds and 14 ounces per classroom.</span>
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3 years ago
find the least common denominator of the following rational expression 1/x-5 , x+3/x^2-10x+25, 7x/x^2-25
I am Lyosha [343]
Hello there!
Find the last common denominator of the following rational expression 1/x-5 , x+3/x^2-10x+25, 7x/x^2-25

Find the LCD.
x^{2} (x-5)(x+5)

Answer: x^{2} (x-5)(x+5)
5 0
3 years ago
The area of a rectangular garden is given by the quadratic function: LaTeX: A\left(x\right)=-6x^2+105x-294A ( x ) = − 6 x 2 + 10
damaskus [11]

Answer:

Step-by-step explanation:

Domain= All real numbers. To get this answer i just plug the x-values into the quadratic formula to get the y-output.

Maximum area=1323/8

Range= y<= 1323/8

3 0
4 years ago
Point A is located at (5, 10) and point B is located at (20, 25).
Alla [95]
Let's say the point is C, so C partitions AB into two pieces, where AC is at a ratio of 3 and CB is at  a ratio of 7, thus 3:7,

\bf \left. \qquad  \right.\textit{internal division of a line segment}&#10;\\\\\\&#10;A(5,10)\qquad B(20,25)\qquad&#10;\qquad 3:7&#10;\\\\\\&#10;\cfrac{AC}{CB} = \cfrac{3}{7}\implies \cfrac{A}{B} = \cfrac{3}{7}\implies 7A=3B\implies 7(5,10)=3(20,25)\\\\&#10;-------------------------------\\\\&#10;{ C=\left(\cfrac{\textit{sum of "x" values}}{\textit{sum of ratios}}\quad ,\quad \cfrac{\textit{sum of "y" values}}{\textit{sum of ratios}}\right)}\\\&#10;-------------------------------

\bf C=\left(\cfrac{(7\cdot 5)+(3\cdot 20)}{3+7}\quad ,\quad \cfrac{(7\cdot 10)+(3\cdot 25)}{3+7}\right)&#10;\\\\\\&#10;C=\left( \cfrac{35+60}{10}~~,~~\cfrac{70+75}{10} \right)\implies C=\left(\cfrac{95}{10}~~,~~\cfrac{145}{10}  \right)&#10;\\\\\\&#10;C=\left( \cfrac{19}{2}~~,~~\cfrac{29}{2} \right)\implies C=\left( 9\frac{1}{2}~~,~~14\frac{1}{2}  \right)
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3 years ago
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