Answer:
How do you solve this?sin 10 = cos ?
1 answer:
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To solve this problem, we have to apply mole-concept to this and we would need the molar mass of AlCl3. 2g of AlCl3 contains 9.034*10^21 molecules.
<h3>Number of Molecules in 2g of AlCl3</h3>The molar mass of AlCl3 is given as 133.34g/mol
Data;
- mass = 2g
- molar mass = 133.34g/mol
Using the mole concept, we can equate the molar mass to the number of molecules present in the entity.
If we equate this
From the calculations above, 2g of AlCl3 contains 9.034*10^21 molecules.
Learn more on mole concept here;
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Answer:
a.) 0.5
b.) 0.66
c.) 0.83
Step-by-step explanation:
As given,
Total Number of Batteries in the drawer = 10
Total Number of defective Batteries in the drawer = 4
⇒Total Number of non - defective Batteries in the drawer = 10 - 4 = 6
Now,
As, a sample of 3 is taken at random without replacement.
a.)
Getting exactly one defective battery means -
1 - from defective battery
2 - from non-defective battery
So,
Getting exactly 1 defective battery = ⁴C₁ × ⁶C₂ = ×
= ×
= ×
= ×
= ×
= 60
Total Number of possibility = ¹⁰C₃ =
=
=
=
= 120
So, probability =
b.)
at most one defective battery :
⇒either the defective battery is 1 or 0
If the defective battery is 1 , then 2 non defective
Possibility = ⁴C₁ × ⁶C₂ = 60
If the defective battery is 0 , then 3 non defective
Possibility = ⁴C₀ × ⁶C₃
= ×
= ×
= 1 ×
= 1×
= 1 × 20 = 20
getting at most 1 defective battery = 60 + 20 = 80
Probability =
c.)
at least one defective battery :
⇒either the defective battery is 1 or 2 or 3
If the defective battery is 1 , then 2 non defective
Possibility = ⁴C₁ × ⁶C₂ = 60
If the defective battery is 2 , then 1 non defective
Possibility = ⁴C₂ × ⁶C₁
= ×
= ×
= ×
= ×
= 6 × 6 = 36
If the defective battery is 3 , then 0 non defective
Possibility = ⁴C₃ × ⁶C₀
= ×
= ×
= × 1
= 4×1 = 4
getting at most 1 defective battery = 60 + 36 + 4 = 100
Probability =