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Karolina [17]
2 years ago
9

Which of the following matches a quadrilateral with the listed characteristics

Mathematics
1 answer:
Masja [62]2 years ago
6 0

The quadrilateral that matches the characteristics is a square.

<h3 />

<h3>What is a quadrilateral?</h3>

A quadrilateral is a 2 dimensional figure with 4 sides. Example of quadrilaterals are rectangle, rhombuses, square, parallelograms and many more.

Therefore, the quadrilateral that matches the characteristics is a square.

Properties of a square

  • It has 4 right angles.
  • It has 4 congruent sides.
  • Both pairs of opposite sides are parallel.

learn more on quadrilateral here: brainly.com/question/13805601

#SPJ1

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The ground temperature at an airport is 13 °C. The temperature decreases by 7 °C for every increase of 1 kilometer above the gro
drek231 [11]
I’m guessing it’s -22
4 0
3 years ago
A sample of 47 observations is selected from a normal population. The sample mean is 30, and the population standard deviation i
erma4kov [3.2K]

Answer:

We accept the null hypothesis and reject  the alternate hypothesis. There is no evidence to conclude that the population mean is greater than 29. The population mean is less than or equal to 29.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 29

Sample mean, \bar{x} = 30

Sample size, n = 47

Alpha, α = 0.05

Population standard deviation, σ = 5

First, we design the null and the alternate hypothesis

H_{0}: \mu \leq 29\\H_A: \mu > 29

a) This is a one-tailed test because the alternate hypothesis is in greater than direction.

We use One-tailed z test to perform this hypothesis.

b) z_{stat} > z_{critical} , we reject the null hypothesis and accept the alternate hypothesis and if z_{stat} < z_{critical} , we accept the null hypothesis and reject  the alternate hypothesis.

c) Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

z_{stat} = \displaystyle\frac{30 - 29}{\frac{5}{\sqrt{47}} } = 1.37

d) Now, z_{critical} \text{ at 0.05 level of significance } = 1.64

Since,  

z_{stat} < z_{critical}

We accept the null hypothesis and reject  the alternate hypothesis. There is no evidence to conclude that the population mean is greater than 29. The population mean is less than or equal to 29.

e) P-value is 0.0853

On the basis of p value we again accept the null hypothesis.

5 0
3 years ago
HELP plz due by 9:00 pm 15 pts. brainliest has to do with ratios.. The polygons are similar. The area of one polygon is given. F
klasskru [66]

Answer:

Step-by-step explanation:

area of smaller triangle=96×(3/12)²=96×1/16=6cm²

8 0
3 years ago
A pet store sells goldfish and hermit crabs,
Elis [28]

Answer:

Cost = \$28

Step-by-step explanation:

Given

Represent Goldfish with g and hermit crabs with h.

The first statement, we have:

7g + 3h = 26

The second statement, we have:

4g + 5h = 28

Required

Determine the selling price of 6 goldfish and 4 hermit crabs

The equations are:

7g + 3h = 26 --- (1)

4g + 5h = 28 --- (2)

Make g the subject in (2)

4g + 5h = 28

4g = 28 - 5h

Divide both sides by 4

g = \frac{1}{4}(28 - 5h)

Substitute \frac{1}{4}(28 - 5h) for g in (1)

7g + 3h = 26

7(\frac{1}{4}(28 - 5h)) + 3h = 26

\frac{7}{4}(28 - 5h) + 3h = 26

Multiply through by 4

4 * \frac{7}{4}(28 - 5h) + 4*3h = 26*4

7(28 - 5h) + 4*3h = 26*4

Open bracket

196 - 35h + 12h = 104

196 -23h = 104

Collect Like Terms

-23h = 104-196

-23h = -92

Make h the subject

h = \frac{-92}{-23}

h = \frac{92}{23}

h = 4

Substitute 4 for h in g = \frac{1}{4}(28 - 5h)

g = \frac{1}{4}(28 - 5*4)

g = \frac{1}{4}(28 - 20)

g = \frac{1}{4}(8)

g = 2

This implies that:

1 goldfish = $2

1 hermit crab = $4

The cost of 6 goldfish and 4 hermit crabs is:

Cost = 6g + 4h

Cost = 6*\$2 + 4*\$4

Cost = \$12 + \$16

Cost = \$28

5 0
3 years ago
Population in Millions
storchak [24]

Answer:

0.486% of world population lives in Canada.

Step-by-step explanation:

Given: World Population= 7691 million.

           Canada Population= 37.4 million.

Now, finding the percentage of world population lives in Canada.

Population\ percentage= \frac{Canada\ population}{World\ population} \times 100

⇒ Population\ percentage= \frac{37.4}{7691} \times 100

⇒ Population\ percentage= 0.00486\times 100

∴ Population\ percentage= 0.486\%

Hence, 0.486% of world population lives in Canada.

5 0
3 years ago
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