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Karolina [17]
2 years ago
9

Which of the following matches a quadrilateral with the listed characteristics

Mathematics
1 answer:
Masja [62]2 years ago
6 0

The quadrilateral that matches the characteristics is a square.

<h3 />

<h3>What is a quadrilateral?</h3>

A quadrilateral is a 2 dimensional figure with 4 sides. Example of quadrilaterals are rectangle, rhombuses, square, parallelograms and many more.

Therefore, the quadrilateral that matches the characteristics is a square.

Properties of a square

  • It has 4 right angles.
  • It has 4 congruent sides.
  • Both pairs of opposite sides are parallel.

learn more on quadrilateral here: brainly.com/question/13805601

#SPJ1

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Kate has gone up to the chalkboard to do math problems 5 more times than Andre. Kate has gone up 11 times. Which equation repres
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 B, because it says she has gone up 5 times Andre (a).
8 0
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Help me with this math question pls!! Find the value of x
vfiekz [6]

Answer:

x = 3

Step-by-step explanation:

using the mid segment formula since quadrilateral WZYP is similar to that of MZYT, this is expressed as;

29 = 1/2(23 +11x+2)

Cross multiply

2(29) =  23+11x+2

58 = 25 + 11x

11x = 58 - 25

11x = 33

Divide both sides by 11

11x/11 = 33/11

x = 3

Hence the value of x is 3

3 0
3 years ago
Researchers at the Centers for Disease Control and Prevention have been studying the decay pattern of a new virus with a decay r
koban [17]

The Researcher will find 69 viruses, because 231 viruses are decayed in 7 hours, if a virus with a decay rate of 19% per hour and they start with 300 viruses.

Step-by-step explanation:

The given is,

                     A new virus with a decay rate of 19% per hour  

                    They start with 300 viruses

Step:1

                  Formula to calculate the viruses at decay rate,

                                                  y = A(1-r)^{t}............................(1)

                 Where, y - No of viruses after given time

                             A - Viruses at initial stage

                              r - Decay rate

                              t - No. of hours

                 From the given,

                              A = 300

                               r = 19% per hour

                               t = 7 hours

                Equation (1) becomes,

                                            y = 300(1-0.19)^{7}

                                               = 300(0.81)^{7}

                                               = 300(0.228767)

                                               = 68.63

               Viruses of 7 hours ≅ 69 viruses

                                                     ( or )

Step:1

        For 1st hour,

          = (No.of viruses in hour) - (No,of viruses in last hour × Decay rate )

              = (300)-(300 × 0.19)

              = 300 - 57

              = 243

       For 2nd hour,

              = (243)-(243 × 0.19)

              = 243 - 46.17

              = 196.83

      For 3rd hour,

              = (196.83)-(196.83 × 0.19)

              = 196.83 - 37.39

              = 159.4323

       For 4th hour,

              = (159.4323)-(159.4323 × 0.19)

              = 159.4323 - 30.2921

              = 129.1402

      For 5th hour,

              = (129.1402)-(129.1402 × 0.19)

              = 129.1402 - 24.5366

              = 104.6035

     For 6th hour,

              = ( 104.6035)-( 104.6035 × 0.19)

              =  104.6035 - 19.8747

              = 84.7288

     For 7th hour,

              = (84.7288)-(84.7288 × 0.19)

              =  84.7288 - 16.0984

              = 68.63 viruses

Result:

          The Researcher will find 69 viruses, because 231 viruses are decayed in 7 hours, if a virus with a decay rate of 19% per hour and they start with 300 viruses.

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The line defined by the equation 7 x + 4 y + 6 =0
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What do you need to find ? x and y ?
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