X^3 -2x^2 -35x
=x(x^2-2x-35)
=x(x-7)(x+5)
<em><u>The inequality can be used to find the interval of time taken by the object to reach the height greater than 300 feet above the ground is:</u></em>
![d = -16t^2 + 1000](https://tex.z-dn.net/?f=d%20%3D%20-16t%5E2%20%2B%201000)
<em><u>Solution:</u></em>
<em><u>The object falls, its distance, d, above the ground after t seconds, is given by the formula:</u></em>
![d = -16t^2 + 1000](https://tex.z-dn.net/?f=d%20%3D%20-16t%5E2%20%2B%201000)
To find the time interval in which the object is at a height greater than 300 ft
Frame a inequality,
![-16t^2 + 1000 > 300](https://tex.z-dn.net/?f=-16t%5E2%20%2B%201000%20%3E%20300)
Solve the inequality
Subtract 1000 from both sides
![-16t^2 + 1000 - 1000 > 300 - 1000\\\\-16t^2 > -700](https://tex.z-dn.net/?f=-16t%5E2%20%2B%201000%20-%201000%20%3E%20300%20-%201000%5C%5C%5C%5C-16t%5E2%20%3E%20-700)
![16t^2 < 700\\\\Divide\ both\ sides\ by\ 16\\\\t^2 < \frac{700}{16}\\\\Take\ square\ root\ on\ both\ sides\\\\t < \sqrt{\frac{700}{16}}\\\\t < \pm 6.61](https://tex.z-dn.net/?f=16t%5E2%20%3C%20700%5C%5C%5C%5CDivide%5C%20both%5C%20sides%5C%20by%5C%2016%5C%5C%5C%5Ct%5E2%20%3C%20%5Cfrac%7B700%7D%7B16%7D%5C%5C%5C%5CTake%5C%20square%5C%20root%5C%20on%5C%20both%5C%20sides%5C%5C%5C%5Ct%20%3C%20%5Csqrt%7B%5Cfrac%7B700%7D%7B16%7D%7D%5C%5C%5C%5Ct%20%3C%20%5Cpm%206.61)
Time cannot be negative
Therefore,
t < 6.61
And the inequality used is: ![-16t^2 + 1000>300](https://tex.z-dn.net/?f=-16t%5E2%20%2B%201000%3E300)
Square
Rectangle
Rhombus
Trapezoid
Kite
They all have a four sides
<span>I think the easiest way to answer all of these is to just go ahead and find the equation of the line first.
I'm pretty sure that by the time you see this problem, you've learned how to find
the
equation of a line that passes through two given points. You have two
points: (2, 100) and (5, 205). The equation of the line through them
is
[ y = 35x + 30 ]. (That's the answer to #8.)
6). The initial membership fee ... the cost for walking in the door and signing up,
before any months, is $30. (Also the y-intercept.)
7). The cost per month is $35. (The slope of the line.)
8). We already did that, up above. [ y = 35x + 30 ].
9). 'x' in the equation is the number of months.
There are 12 months in one year.
y = 35(12) + 30 = $450</span>
2(5-n) can be an expression of "twice the difference of 5 and n".