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1 year ago

15

A. 10B. 11C. 12D. 13

1 answer:

irina1246 [14]1 year ago

4 0

Answer:

D. 13

Step-by-step explanation:

13 is the answer I guess I hope it will be the right answer

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2x-4=10 reverse order algebra

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Answer:

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Step-by-step explanation:

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Read 2 more answers

Let f(x)=x^2+6x−16.<br> Enter the x-intercepts of the quadratic function in the boxes.

Sauron [17]

$\underline{\underline{\large\bf{Given:-}}}$

$\red{\leadsto}\:$ $\textsf{}$ $\sf f(x)= x^2+6x−16$

$\underline{\underline{\large\bf{To Find:-}}}$

$\orange{\leadsto}\:$ $\textsf{ x-intercepts of the quadratic function }$ $\sf$

$\\$

$\underline{\underline{\large\bf{Solution:-}}}\\$

$\longrightarrow$ x- intercept is the point where graph of given function touches the x-axis,f(x) becomes 0 at the point where graph of given function touches the x-axis. Therefore, we would to solve x^2+6x−16=0 and find its root.

$\begin{gathered}\\\implies\quad \sf x^2+6x−16=0 \\\end{gathered}$

$\begin{gathered}\\\implies\quad \sf x^2+8x-2x −16=0 \\\end{gathered}$

$\begin{gathered}\\\implies\quad \sf x(x+8)-2(x+8)=0 \\\end{gathered}$

$\begin{gathered}\\\implies\quad \sf (x-2)(x+8)=0\\\end{gathered}$

$\begin{gathered}\\\implies\quad \sf x=2\quad or \quad x=-8 \\\end{gathered}$

$\leadsto$ x-intercepts of the given quadratic function are 2 and -8 .

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Step-by-step explanation:

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