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VARVARA [1.3K]
3 years ago
8

A circle has its center at (0,0) and passes through the point (0,9). What is the standard equation of the circle?

Mathematics
1 answer:
vitfil [10]3 years ago
6 0

Answer:

Step-by-step explanation:

I believe the answer is x² + y² = 9²

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Can earn 5 coins
Aleonysh [2.5K]

Answer:4.14

Step-by-step explanation:

4 0
3 years ago
A 6-yard piece of ribbon costs $36.72. What is the price per foot?
djyliett [7]

Answer:

$2.04

Step-by-step explanation:

Note that: 1 yard = 3 feet.

First, change the amount of yard (6) to feet:

6 x 3 = 18

6 yard = 18 feet.

Note: 18 feet = $36.72

Find the cost per foot (1 feet). Note the equal sign, what you do to one side, you do to the other. Divide 18 from both sides.

(18 ft)/18 = ($36.72)/18

1 ft = 36.72/18

1 ft = 2.04/1

1 ft = $2.04

~

4 0
3 years ago
Read 2 more answers
3 intersecting lines are shown. A line contains points E, D, A, and B. Another line intersects the line at point A and contains
GREYUIT [131]

Answer:

The one with arrows are the answers

->Line segment E B  is bisected by Line segment D F .

->A is the midpoint of Line segment F C .

Line segment F C  bisects Line segment D B.

->Line segment E B  is a segment bisector.

->FA = One-halfFC.

Line segment D A is congruent to Line segment A B .

Step-by-step explanation:

I did it on edge and got it right

5 0
3 years ago
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A line passes through the point (2, 10) and has a y-intercept of 4. What is the equation of the line? Help me please
joja [24]

Step-by-step explanation:

If it's a straight line the use formula

y = mx + c

m= gradient of line

c = y-intercept

we know that y-intercept is 4 so coordinate is

(0,4)

Equation also passes (2,10)

Use both coordinate to find gradient

m= vertical distance / horizontal distance

= (10-4) / (2-0)

= 3

y = 3x + 4

6 0
3 years ago
Find the interquartile range for the data {5, 7, 9, 5, 6, 6, 6, 11, 11, 3, 3}
RoseWind [281]

Answer:

4

Step-by-step explanation:

i dont really know how to explain i used an algebra calculator

4 0
3 years ago
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