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Rina8888 [55]
3 years ago
6

Normally the rate at which you expend energy during a brisk walk is 3.6 Calories per minute. (A Calorie is the common unit of fo

od energy, equal to 4184.1 J.) How long do you have to walk to produce the same amount of energy as a 150 W lightbulb that is lit for 5.8 hours?
Mathematics
1 answer:
Sindrei [870]3 years ago
7 0

Answer:

3.5 hour

Step-by-step explanation:

During a brisk walk, rate at which energy is expended is P(expend) = 3.6 calories per min

1 calorie = 4184.1 J

Energy produced by bulb is P(bulb) = 150W

time = 5.8 hrs

Convvert 5.8 hrs to secs. we have

t = 5.8*3600

t= 20880 secs

Power = Energy/time

150 = energy / 20880

Energy = 150 * 20880

= 3132000J

Convert the rate at which cv h energy is expended into joules per second, we have

(3.6 * 4184.1)/60

P(expend) = 251J/s

= 251W

Recall that P = E/t

t = E/p

t = 3132000/251

t = 12478 secs

Convert secs to hour

t = 12478/ 3600

t= 3.5 hours

The time requtied to produce the s\me amount of energy as 150W bulb that lights up 5..8hrs is t = 3.5 hrs

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If f(x) = 2x - 2 and g(x) = x}, what is (gºf)(4)?
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Answer:

We conclude that:

(gºf)(4) = g(f(4)) = g(6) = 6

Step-by-step explanation:

Given

f(x) = 2x - 2

g(x) = x

We have to determine (gºf)(4).

(gºf)(4) = g(f(4))

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(gºf)(4) = g(f(4)) = g(6) = 6

Therefore, we conclude that:

(gºf)(4) = g(f(4)) = g(6) = 6

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Determine the inequality that can be used to model when the population of bacteria will be greater than or equal to 656,100. The
jenyasd209 [6]

The inequality is 100*3^{t}≤ 656100.

The correct option is (B).

<h3>What is inequality?</h3>

A statement of an order relationship—greater than, greater than or equal to, less than, or less than or equal to—between two numbers or algebraic expressions.

Given:

From the table attached below:

a=300, r= 900/300 = 3

As, it is GP

Now,

f(t) = ar^{t-1}

f(t) = 300*3^{t-1}

f(t) = 300/3 *3^{t}

f(t) = 100*3^{t}

Inequality is used to determine greater than or equal to 656100

100*3^{t}≤ 656100

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