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2 years ago

What is the distance between (7,2) and (-3,2)? A.8 B.12 C.4 D.10

2 answers:

6 0

The answer is D (10)

Explanation:

Let (7, 2) be (x1, y1) and (-3, 2) be (x2, y2)

Using the Distance Formula,
d = sqrt[(x2 - x1)^2 + (y2 - y1)^2]
= sqrt[(- 3 - 7)^2 + (2 - 2)^2]
= sqrt[(-10)^2 + 0]
= sqrt[100]
= 10 units

deff fn [24]2 years ago

4 0

Answer:

The answer is D

......(don't mind this it's because it says that it needs to be 20 characters long) but the answer is D

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What geometric construction is shown below

AnnyKZ [126]

Answer:

doubling the square Apex

Step-by-step explanation:

5 0

2 years ago

Angle 1 and Angle 2 are supplementary. If m∠1=27° , what is m∠2 ?

nekit [7.7K]

Suppose m∠1 = x degree

m∠2 = 17 x degree

As angle 1 & 2 are supplementary angles so

m∠1 +m∠2 =180 degree...... eq 1
Substituting the values of angle 1 & 2 in eq 1, we get

x +17x =180
18x=180
x= 180/18 =10 degree
17 x= 170 degree
m∠1 = 10 degree m∠2 = 170 degree.

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2 years ago

The frequency distributions of two data sets are shown in the dot plots below.

fredd [130]

Answer:

1st, 4th and 6th statements are true.

Step-by-step explanation:

We have been given two dot-plots and we are asked to select all the true statements about given dot plots.

Let us write all the data points of both dot plots.

Data set 1:

1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4, 7.

Data set 2:

1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4.

1. The mean of data set 1 is greater than the mean of data set 2.

Let us find mean of both data sets.

$\text{Mean of data set 1}=\frac{1+1+1+1+1+2+2+2+2+2+2+2+2+3+3+3+4+4+7}{19}$

$\text{Mean of data set 1}=\frac{45}{19}$

$\text{Mean of data set 1}=2.3684\approx 2.37$

$\text{Mean of data set 2}=\frac{1+1+1+1+1+2+2+2+2+2+2+2+2+3+3+3+4+4}{18}$

$\text{Mean of data set 2}=\frac{38}{18}$

$\text{Mean of data set 2}=2.11$

We can see that mean of data set 1 is greater than mean of data set 2, therefore, 1st statement is true.

2. The mean of data set 1 is equal to the mean of data set 2.

Since mean of data set 1 is greater than mean of data set 2, therefore, 2nd statement is false.

3. The median of data set 1 is greater than the median of data set 2.

Since data set 1 has 19 data points, so median of data set 1 will be value of 10th data set, that is 2.

Our data set 2 has 18 data points, so median of data set 2 will be the average of 9th and 10th data points.

$\text{Median of data set 2}=\frac{2+2}{2}$

$\text{Median of data set 2}=\frac{4}{2}=2$

Since median of data set 2 is also 2, therefore, 3rd statement is not true.

4. The median of data set 1 is equal to the median of data set 2.

Since both data set's median is 2, therefore, 4th statement is true.

5. The standard deviation of data set 1 is smaller than the standard deviation of data set 2.

Using online SD calculator we get SD of data set 1 is 1.422 and SD of data set 2 is 0.936. Since 1.422 is greater than 0.936, therefore, 5th statement is false.

6. The data sets have the same interquartile range.

$Q_1\text{ of data set 1}=1$