1) Company A and C
2)Your answer is f(t) = 180(0.5)^t This is because the number is cut in half for every hour.
3)C 0 ≤ x ≤ 50 is the right answer because the starting time 9:05 is considered as zero and the 9:55 is the ending point which is considered as 50.Or simply the difference of both the times is the domain of the function.
Answer:
I know that the equation has infinity many solution
12x+8=12x+8
That would be the final answer
to convert a fraction to a decimal, like say a/b is really simply the quotient of a ÷ b.
now, let's first convert the mixed fraction to improper, and then do the division.
![\bf \stackrel{mixed}{5\frac{5}{16}}\implies \cfrac{5\cdot 16+5}{16}\implies \stackrel{improper}{\cfrac{85}{16}}\\\\[-0.35em] \rule{31em}{0.25pt}\\\\ \cfrac{85}{16}\implies 85\div 16\implies 5.3125](https://tex.z-dn.net/?f=%20%5Cbf%20%5Cstackrel%7Bmixed%7D%7B5%5Cfrac%7B5%7D%7B16%7D%7D%5Cimplies%20%5Ccfrac%7B5%5Ccdot%2016%2B5%7D%7B16%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B85%7D%7B16%7D%7D%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B31em%7D%7B0.25pt%7D%5C%5C%5C%5C%20%5Ccfrac%7B85%7D%7B16%7D%5Cimplies%2085%5Cdiv%2016%5Cimplies%205.3125%20)
Answer:
11.11% probability that it will rain on the day of Marie's wedding, given the weatherman forecasts rain
Step-by-step explanation:
Bayes Theorem:
Two events, A and B.

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.
In this question:
Event A: Forecast of rain.
Event B: Raining.
In recent years, it has rained only 5 days each year.
A year has 365 days. So

When it actually rains, the weatherman correctly forecasts rain 90% of the time.
This means that 
Probability of forecast of rain:
90% of 0.0137(forecast and rains)
10% of 1 - 0.0137 = 0.9863(forecast, but does not rain)

What is the probability that it will rain on the day of Marie's wedding, given the weatherman forecasts rain

11.11% probability that it will rain on the day of Marie's wedding, given the weatherman forecasts rain