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GuDViN [60]
3 years ago
5

The length of a rectangle is (x+3) inches long,and the width is 3⅖ inches.If the area is 15 3/10 square inches,write an equation

to find the lenght of rectangle
Mathematics
1 answer:
tino4ka555 [31]3 years ago
8 0

Answer:

(x + 3) = 9/2

Step-by-step explanation:

Here, we want to write an equation to find the length of the rectangle

Mathematically;

Area of rectangle = length * breadth

15 3/10 = (x + 3) * 3 2/5

(x + 3) = 15 3/10 divided by 3 2/5

(x + 3) = 153/10 * 5/17

(x + 3) = 9/2

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The ratio of dogs to cats at an animal shelter is 7 to 5. how many cats are at the shelter if there are 42 more dogs than cats,
Zanzabum
105 cats are in the shelter as 1 = 21 x 5
7 0
3 years ago
Can someone help with this question
NikAS [45]
1st : Find the volume of the rectangular block:
12 × 10 × 20 = 2400 cm^3.

2nd : Find the volume of a cylinder
\pi  {r}^{2} h
Where r is radius & h is height.
so:
\pi \times 2.2 {}^{2}  \times 5.0
= 76.02654222 cm^3

Lastly, divide the volume of the rectangular block by the volume of the cylinder
2400 ÷ 76.026 = 31.5679226

You can't round it up so the answer is F) 31
4 0
3 years ago
PLEASE HELP ASAP
makkiz [27]

Answer:

5

Step-by-step explanation:

Since the difference in each term number is 5, we put 5 in the place of the star.

Formula for constant difference in a pattern: Tn= an+b

a is the difference while b is the number that comes before the 1st term. So, the equation to find the nth term is Tn=5n+4.

Hope this helps and please give a brainlist, thank you!

5 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%7B%7D%5E%7B2%7D%20-%204%20%7D%7B%20%5Csqrt%7Bx%20%7B%7D%5E%7B2%7D%20-%206x%2
Nimfa-mama [501]

First of all, we can observe that

x^2-6x+9 = (x-3)^2

So the expression becomes

\dfrac{x^2-4}{\sqrt{(x-3)^2}} = \dfrac{x^2-4}{|x-3|}

This means that the expression is defined for every x\neq 3

Now, since the denominator is always positive (when it exists), the fraction can only be positive if the denominator is also positive: we must ask

x^2-4 \geq 0 \iff x\leq -2 \lor x\geq 2

Since we can't accept 3 as an answer, the actual solution set is

(-\infty,-2] \cup [2,3) \cup (3,\infty)

7 0
2 years ago
Vary hard 6th grade work
DochEvi [55]
And uh the work? Lol
3 0
3 years ago
Read 2 more answers
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