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2 years ago

What event occurred closest in the time to the sinking of the Titanic?

Engineering

1 answer:

stich3 [128]2 years ago

3 0

Answer:

WW|

Explanation:

Titanic sank on 1912 and the event that occurred closest on this date based on what is listed below the question is World War 1 which was on 1914.

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5x−2y=30 Complete the missing value in the solution to the equation. (8, )

givi [52]

Answer:

Value of y = 5

(8,5)

Explanation:

Given:

5x−2y=30

Value of x = 8

Find:

Value of y

Computation:

⇒ 5x−2y=30

⇒ 5(8)−2y=30

⇒ 40−2y=30

⇒ -2y = -10

y = 5

Value of y = 5

(8,5)

4 0

3 years ago

Air at 1 atm enters a thin-walled ( 5-mm diameter) long tube ( 2 m) at an inlet temperature of 100°C. A constant heat flux is ap

alexdok [17]

Answer:

heat rate = 7.38 W

Explanation:

Given Data:

Pressure = 1atm

diameter (D) = 5mm = 0.005m

length = 2

mass flow rate (m) = 140*10^-6 kg/s

Exit temperature = 160°C,

At 400K,

Dynamic viscosity (μ) = 22.87 *10^-6

Prandtl number (pr) = 0.688

Thermal conductivity (k) = 33.65 *10^-3 W/m-k

Specific heat (Cp) = 1.013kj/kg.K

Step 1: Calculating Reynolds number using the formula;

Re = 4m/πDμ

= (4*140*10^-6)/(π* 0.005*22.87 *10^-6)

= 5.6*10^-4/3.59*10^-7

= 1559.

Step 2: Calculating the thermal entry length using the formula

Le = 0.05*Re*Pr*D

Substituting, we have

Le = 0.05 * 1559 * 0.688 *0.005

Le = 0.268

Step 3: Calculate the heat transfer coefficient using the formula;

Nu = hD/k

h = Nu*k/D

Since Le is less than given length, Nusselt number (Nu) for fully developed flow and uniform surface heat flux is 4.36.

h = 4.36 * 33.65 *10^-3/0.005

h = 0.1467/0.005

h = 29.34 W/m²-k

Step 4: Calculating the surface area using the formula;

A = πDl

=π * 0.005 * 2

=0.0314 m²

Step 5: Calculating the temperature Tm

For energy balance,

Qc = Qh

Therefore,

H*A(Te-Tm) = MCp(Tm - Ti)

29.34* 0.0314(160-Tm) = 140 × 10-6* 1.013*10^3 (Tm-100)

0.921(160-Tm) = 0.14182(Tm-100)

147.36 -0.921Tm = 0.14182Tm - 14.182

1.06282Tm = 161.542

Tm = 161.542/1.06282

Tm = 151.99 K

Step 6: Calculate the rate of heat transferred using the formula

Q = H*A(Te-Tm)

= 29.34* 0.0314(160-151.99)

= 7.38 W

the Prandtl number using the formula

5 0

3 years ago

Problem 1 (10 points) In the first homework you were instructed to design the mechanical components of an oscillating compact di

Ilya [14]

Answer:

Problem 1 (10 points) In the first homework you were instructed to design the mechanical components of an oscillating compact disc reader. Since you did such a good job in your design, the company decided to work with you in their latest Blue-ray readers, as well. However, this time the task is that once the user hits eject button, the motor that spins the disc slows down from 2000 rpm to 300 rpm and at 300 rpm a passive torsional spring-damper mechanism engages to decelerate and stop the disc. Here, your task is to design this spring-damper system such that the disc comes to rest without any oscillations. The rotational inertia of the disc (J) is 2.5 x 10-5kg m² and the torsional spring constant (k) is 5 × 10¬³NM. Calculate the critical damping coefficient cc for the system. choice of the damper, bear in mind that a good engineer stays at least a factor of In your 2 away from the danger zone (i.e., oscillations in this case). Use the Runge Kutta method to simulate the time dependent angular position of the disc, using the value of damping coefficient (c) that calculated. you Figure 1: Blue-ray disc and torsional spring-damper system.

5 0

3 years ago

(20 points) (Assessment of Outcome 1): A plant has two identical standby generator units for emergency use. In the area of the g

erastovalidia [21]

Answer:

It wouldn't get any louder then maybe 3db more

Explanation:

There's even a equation if you wanted to check this out but, if they are the same generator same model and all and made the same precise noise it wouldn't increase more then 3db.

5 0

3 years ago

Which statement about direct-mail messages is most accurate? Group of answer choices Direct mail is an effective channel for per

torisob [31]

Answer:

Option A

Direct mail is an effective channel for personalized, tangible, three-dimensional messages that are less invasive than telephone solicitations

Explanation:

In modern days, we've seen email marketing hence option B that "Today's companies no longer send direct-mail messages to market their products or services; they rely exclusively on electronic media instead." These companies rely also on direct mails to their clients. Online marketing often uses direct mail for persuasion of their customers hence the last option is also wrong. Considering that already two statements are identified as inaccurate, the option that "All answer choices are accurate statements about direct-mail messages. " is misleading. Therefore, the only most accurate choice about direct-mail is option A

4 0

4 years ago