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3 years ago

What is the sum of A+B+ C

Engineering

1 answer:

Liono4ka [1.6K]3 years ago

5 0

Answer:

in pyphagoreom therom it is A sqared Plus B sqared eqauls c scrared

Explanation:

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The inlet for a high-bypass-ratio turbofan engine has an area A1 of 6.0 m 2 and is designed to have an inlet Mach number M~ of 0

Lelu [443]

Answer:

The additive drag at flight condition will be found by the following equation

Area = A1 = 6m2

Da = Additive drag

Cda = Additive drag coefficient

P = prassure at altitude of 12Km

Po = Prassure at sea level

\gamma = Ratio of specific heat capacity

The formula of additive drag is given below

D = Cda q A

q = Dynamic prassure , A = cross sectional area

q =( \gamma/ 2) P0 M02

D = Cda ( \gamma/2) po Mo2 A

Cda=0.32

\gamma=1.4

M=0.8

p0= 101325pa

D = 0.32 (1.4/2)(101325pa)(0.6)2 6

D = 49025N

Explanation:

The additive drag at the flight conditions will be D= 49025N

8 0

3 years ago

g a heat engine is located between thermal reservoirs at 400k and 1600k. the heat engine operates with an efficiency that is 70%

Bond [772]

Answer:

Heat rejected to cold body = 3.81 kJ

Explanation:

Temperature of hot thermal reservoir Th = 1600 K

Temperature of cold thermal reservoir Tc = 400 K

efficiency of the Carnot's engine = 1 - $\frac{Tc}{Th}$

eff. of the Carnot's engine = 1 - $\frac{400}{600}$

eff = 1 - 0.25 = 0.75

efficiency of the heat engine = 70% of 0.75 = 0.525

work done by heat engine = 2 kJ

eff. of heat engine is gotten as = W/Q

where W = work done by heat engine

Q = heat rejected by heat engine to lower temperature reservoir

from the equation, we can derive that

heat rejected Q = W/eff = 2/0.525 = 3.81 kJ

6 0

3 years ago

A stainless steel ball (=8055 kg/m3, Cp= 480 J/kgK) of diameter D =15 cm is removed from theoven at a uniform temperature of 3

aleksandrvk [35]

Answer:

i) 25.04 W/m^2 .k

ii) 23.82 minutes = 1429.2 secs

Explanation:

Given data:

Diameter of steel ball = 15 cm

uniform temperature = 350°C

p = 8055 kg/m^3

Cp = 480 J/kg.k

surface temp of ball drops to 250°C

average surface temperature = ( 350 + 250 ) / 2 = 300°C

i) Determine the average convection heat transfer coefficient during the cooling process

Note : Obtain the properties of air at 1 atm at average film temp of 30°C from the table " properties of air " contained in your textbook

average convection heat transfer coefficient = 25.04 W/m^2 .k

ii) Determine how long this process has taken

Time taken by the process = 23.82 minutes = 1429.2 seconds

Δt = Qtotal / Qavg = 683232 / 477.92 = 1429.59 secs

attached below is the detailed solution of the given question

3 0

3 years ago

THE MASS FOR OBJECT 1 is 107.01 grams what is the objects force in Newton’s answer please

Aleksandr [31]

Given that,

Mass of the object 1, m = 107.01 grams

To find,

Force on the object.

Solution,

The force acting on the object is gravitational force. The force is given by the formula as follow :

F = mg

g is acceleration due to gravity

F = 0.10701 kg × 9.8 m/s²

F = 1.048 N

So, the force acting on object 1 is 1.048 N.

5 0

3 years ago

Air is compressed slowly in a piston-cylinder assembly from an initial state where P1 = 1.4 bar, V1= 4.25 m^3, to a final state

lord [1]

Answer:

W=-940.36 KJ

Explanation:

Given that

$P_1=1\ bar,V_1=4.25 {m^3}$

$P_2=6.8\ bar$

Process follows pv=constant

So this is the isothermal process and work in isothermal process given as

$W=P_1V_1\ln \dfrac{P_1}{P_2}$

Now by putting the values (1.4 bar =140 KPa)

$W=P_1V_1\ln \dfrac{P_1}{P_2}$

$W=140\times 4.25 \ln \dfrac{1.4}{6.8}$

W=-940.36 KJ

Negative sign indicates that this is a compression process and work will given to the system.

7 0

4 years ago