Answer:
864 KN
Explanation:
Atmospheric pressure is defined as the force per unit area exerted against a surface by the weight of the air above that surface.
Please kindly check attachment for the step by step solution of the given problem.
Answer:
a) I=0 b) 4.17V c) 0.354 A d) 14.5s
Explanation:
a) consider circuit in the attachment
i(t)= E/R (1- e^(-t/RL))
i(0)= 12.5/3×(1-e^(0/RL))
i(0)=0
b) at t⇒∞
i(∞)= 12.5/3× (1- e^(-∞/RL))
= 4.17V
c) 1/RL= 1/(6.95×3)= 0.0479616
i(1.85) = 12.5/3 × (1- e^(-1.85×0.0479616)
= 0.354A
d) I/2= I (1- e^(-t/RL))
t= - RL ln0.5
t= - 3×6.95 × (-0.693)
t= 14.5 s
Answer:
The tube diameter is 2.71 mm.
Explanation:
Given:
Open glass tube is inserted into a pan of fresh water at 20°C.
Height of capillary raise is four times tube diameter.
h = 4d
Assumption:
Take water as pure water as the water is fresh enough. So, the angle of contact is 0 degree.
Take surface tension of water at 20°C as
N/m.
Take density of water as 100 kg/m3.
Calculation:
Step1
Expression for height of capillary rise is gives as follows:
Step2
Substitute the value of height h, surface tension, density of water, acceleration due to gravity and contact angle in the above equation as follows:
m.
Or
d=2.719 mm
Thus, the tube diameter is 2.719 mm.
In a Class Three Lever, the Force is between the Load and the Fulcrum. If the Force is closer to the Load, it would be easier to lift and a mechanical advantage. Examples are shovels, fishing rods, human arms and legs, tweezers, and ice tongs. A fishing rod is an example of a Class Three Lever.
Answer:
1 13/64
Explanation:
The depth of the hole is the height of the block less the remaining material below the hole:
depth = 1 3/8 +1 15/16 - 3/8 = (1 3/8 -3/8) +1 15/16 = 2 15/16
We want to find the difference between this depth and the depth of the hole already drilled:
2 15/16 -1 47/64 = 2 60/64 -1 47/64
= (2 -1) +(60 -47)/64 = 1 13/64
The hole must be drilled 1 13/64 deeper to match the drawing.