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2 years ago

What is the difference between absorbed wavelengths and reflected wavelengths?

1 answer:

6 0

A reflected wavelength of light is detected by the detector and is decoded as a logic one; absorbed or transmitted wavelengths are not detected, there absence being decoded as a logic zero.

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Buildings designed to partially heat rooms by passive solar heating rely on

Paha777 [63]

Explanation:Image result for buildings designed to partially heat rooms by passive solar heating rely on

A strictly passive design will use the three natural heat transfer modes exclusively—conduction, convection, and radiation. In some applications, however, fans, ducts, and blowers may help with the distribution of heat through the building

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3 years ago

1. What is resilience engineering and how does it pertain to the current<br>corona virus crisis?

saw5 [17]

Answer:

the ability to absorb or avoid damage without suffering complete failure and is an objective of design, maintenance and restoration for buildings and infrastructure

Explanation:

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3 years ago

Which of the following describes how the author introduces dust storms in the text??

Oduvanchick [21]

Answer:

B-as deadly storms that claim lives in th great pines

Explanation:

I hope it helped if it did pls make me brainliest

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3 years ago

Read 2 more answers

2.) A fluid moves in a steady manner between two sections in a flow

Talja [164]

Answer:

$250\ \text{lbm/min}$

$625\ \text{ft/min}$

Explanation:

$A_1$ = Area of section 1 = $10\ \text{ft}^2$

$V_1$ = Velocity of water at section 1 = 100 ft/min

$v_1$ = Specific volume at section 1 = $4\ \text{ft}^3/\text{lbm}$

$\rho$ = Density of fluid = $0.2\ \text{lb/ft}^3$

$A_2$ = Area of section 2 = $2\ \text{ft}^2$

Mass flow rate is given by

$m=\rho A_1V_1=\dfrac{A_1V_1}{v_1}\\\Rightarrow m=\dfrac{10\times 100}{4}\\\Rightarrow m=250\ \text{lbm/min}$

The mass flow rate through the pipe is $250\ \text{lbm/min}$

As the mass flowing through the pipe is conserved we know that the mass flow rate at section 2 will be the same as section 1

$m=\rho A_2V_2\\\Rightarrow V_2=\dfrac{m}{\rho A_2}\\\Rightarrow V_2=\dfrac{250}{0.2\times 2}\\\Rightarrow V_2=625\ \text{ft/min}$

The speed at section 2 is $625\ \text{ft/min}$ .

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3 years ago

Describe how to mix and apply body filler?

malfutka [58]

This is all you need to mix body filler.
Start with a golf-ball size glob of filler.
Squeeze a ribbon of hardner across the filler.
Stir the mixture quickly, but do not "whip" it. ...
Mix until overall color is even.
Pick up an appropriate amount of filler for the task at hand.

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3 years ago