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Alinara [238K]
4 years ago
14

During an unsteady-flow process, the amount of mass and energy entering a control volume must be equal to the amount of mass and

energy leaving a control volume (choose one): Select one: a. True b. False
Engineering
2 answers:
Mazyrski [523]4 years ago
6 0

Answer:

<em>(B) False</em>

Explanation:

<em>An unstable flow is a flow process where the properties of the flow is not stable. from this example or question, the input flow output flow  are not equal or the same</em>

<em>Unstable flow is can be refereed  as a flow that is transient. because  the main properties of interest which includes the volume of the flow through the pipe is not the same so this type of low gives more concern to the person carrying out the study, and  time of flow.</em>

SSSSS [86.1K]4 years ago
3 0

Answer:

False

Explanation: An unstable flow is a flow process where the properties of the flow is unstable, in this case the flow input and flow output are not equal.

Unstable flow is also known as transient flow process because the main properties of interest which includes the time of flow and the volume of the flow through the pipe is not the same so this type of low gives more concern to the person carrying out the study.

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The efficiency of a steam power plant can beincreased by bleeding off some of the steam thatwould normally enter the turbine and
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Answer:

Explanation:

This is Answer....

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3 years ago
A storage tank, used in a fermentation process, is to be rotationally molded from polyethylene plastic. This tank will have a co
NNADVOKAT [17]

Answer:

The volume up to cylindrical portion is approx  32355 liters.

Explanation:

The tank is shown in the attached figure below

The volume of the whole tank is is sum of the following volumes

1) Hemisphere top

Volume of hemispherical top of radius 'r' is

V_{hem}=\frac{2}{3}\pi r^3

2) Cylindrical Middle section

Volume of cylindrical middle portion of radius 'r' and height 'h'

V_{cyl}=\pi r^2\cdot h

3) Conical bottom

Volume of conical bottom of radius'r' and angle \theta is

V_{cone}=\frac{1}{3}\pi r^3\times \frac{1}{tan(\frac{\theta }{2})}

Applying the given values we obtain the volume of the container up to cylinder is

V=\pi 1.5^2\times 4.0+\frac{1}{3}\times \frac{\pi 1.5^{3}}{tan30}=32.355m^{3}

Hence the capacity in liters is V=32.355\times 1000=32355Liters

3 0
4 years ago
Q#1: Provide an example of a software project that would be amenable to the following models. Be specific. a. Waterfall b. Proto
mote1985 [20]

Answer:

Waterfall model

Explanation:

The waterfall model is amenable to the projects. It focused on the data structure. The software architecture and detail about the procedure. It will interfere with the procedure. It interfaces with the characterization of the objects. The waterfall model is the first model that is introduced first. This model also called a linear sequential life cycle model.

The waterfall model is very easy to use. This is the earliest approach of the SDLC.

There are different phase of the waterfall:

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4 0
3 years ago
Why is tubing sometimes coiled when installed in a car or vechile
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Coiled tubing is often used to carry out operations similar to wire lining.

8 0
3 years ago
an amplifier has an input resistance of 100k a short-circuit transconductance of 10 mA/V and an output resistance of 100k. Find
Vlada [557]

Answer:

The open circuit voltage gain is A_{vo}=-10^{3}

Explanation:

Given data is input resistance of an amplifier is R_{in}=100kΩ and output resistance of an amplifier is R_{o} =100kΩ.

Trans conductance of an amplifier is g_{m}=10mA/V

Thus Open circuit voltage gain is

A_{vo} =-g_{m}R_{o}

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Since 1m=10^{-3} and 1k=10^{3}

Thus,

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3 0
3 years ago
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