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valentina_108 [34]
2 years ago
8

How do we know if the line y=x has a postive slope?

Mathematics
2 answers:
Serjik [45]2 years ago
8 0
A line has a positive slope if it is slanting upward, toward the right. A line has a negative slope if it is slanting upward, toward the left.
8_murik_8 [283]2 years ago
3 0
It should be scaling upward.
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State if a triangle is acute, obtuse, or right.
almond37 [142]
The answer is A) Right because the lengths 3 cm and 3 cm are obviously the same so it will form a right angle
6 0
3 years ago
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Mr. Sullivan places tiles numbered 1 through 18 in a bag and assigns a number to represent each of the 18 students in his class.
Marat540 [252]

Answer:

Mr. Sullivan <u>is</u> being fair because one tile has <u>an equal</u> probability of being selected over another tile.

Step-by-step explanation:

The process is fair because every tile has the same probability of being selected, and as the selection goes on, the selected students are removed.

5 0
3 years ago
What is the area of a rectangle with vertices at ​ (0, −4) ​, ​ (−1, −3) ​ , (2, 0) , and (3, −1) ? Enter your answer in the box
Bad White [126]

We are given vertices of a rectangle (0, −4) ​, ​ (−1, −3) ​ , (2, 0) , and (3, −1).

Length is the distance between (0, −4) ​and ​ (−1, −3) points.

Width is distance between  (−1, −3) ​ and (2, 0) points.

<u>Computing length:</u>

\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

=\sqrt{\left(-1-0\right)^2+\left(-3-\left(-4\right)\right)^2}

=\sqrt{2}

<u>Computing Width :</u>

\mathrm{The\:distance\:between\:}\left(-1,\:-3\right)\mathrm{\:and\:}\left(2,\:0\right)\mathrm{\:is\:}

=\sqrt{\left(2-\left(-1\right)\right)^2+\left(0-\left(-3\right)\right)^2}

=3\sqrt{2}

<h3>Area of the rectangle = Length × Width  </h3>

= \sqrt{2} \times 3\sqrt{2} = 3 \times 2 = 6 \ squares \ units..


7 0
3 years ago
Approximate the real zeros to the nearest tenth: a.-1.6, 1.6 c.-2.6, 2.6 b.-2, 1 d .-1.6, 2.6 Please select the best answer from
Mariana [72]

Answer:

You didn't give the expression whose zero you want to find. From the options you wrote, the expression has two zeros, this means it is a quadratic expression.

I will however explain how to find the zero of a quadratic expression.

Step-by-step explanation:

An expression is called quadratic, if the highest degree of the variable is 2, no more, no less. It is of the form: ax² + bx + c, where a, b, and c are constants.

The zeros of a quadratic expression are the values that make the expression vanish, that is equal to zero.

Example: Find the zeros of 2x² - 6x + 4

First, equate the expression to zero

2x² - 6x + 4 = 0

Next, solve for x

2x² - 2x - 4x + 4 = 0

2x(x - 1) - 4(x - 1) = 0

(2x - 4)(x - 1) = 0

(2x - 4) = 0

Or

(x - 1) = 0

2x - 4 = 0

2x = 4

=> x = 4/2 = 2

Or

x - 1 = 0

x = 1

Therefore, the zeros of the polynomial are 1 and 2.

3 0
3 years ago
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Is there an ordered pair that is a solution to BOTH of
Korolek [52]

Answer:

y = -1/2 x + 6

Step-by-step explanation:

2x + 4y = 24

4y = -2x + 24

divide each expression by 4

y = - 1/2x + 6

8 0
2 years ago
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