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VARVARA [1.3K]
2 years ago
6

40 points help me please

Mathematics
2 answers:
andrew11 [14]2 years ago
8 0

Answer: X=60

Step-by-step explanation:

Alinara [238K]2 years ago
4 0

Answer:

x=60

Step-by-step explanation:

(1/6)(x+6)=11

Multiply both sides by six:

(6)(1/6)(x+6)=11(6)

x+6=66

Take six from both sides:

x+6-6=66-6

x=60

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The answer is .00934 hope this helped! 

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3 years ago
Rewrite each expression by factoring out the coefficient of variable -2x+3
Nimfa-mama [501]

By factoring out the coefficient of variable, -2x+3 can be written as -2(x-\frac{3}{2}).

Factoring out means isolating a common factor from an expression. A number or a variable that is multiplied by another variable in the expression forms the coefficient. The factoring out of the coefficient of variable means taking the factor of the coefficient part of the variable term.

Given data is an expression -2x+3.

-2 is the coefficient of variable x. So, factoring out the (-2) from -2x+3:

It can be written as -2(x-\frac{3}{2} )

Hence, -2x+3 can be written  -2(x-\frac{3}{2}) by factoring out the coefficient of variable.

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10 months ago
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s2008m [1.1K]

Answer:

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Step-by-step explanation:

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7 0
2 years ago
The scatter plot below displays the elevation and mean number of clear days per year of 14 U.S. cities. Two lines
Novay_Z [31]

Answer:

=

Step-by-step explanation:

Students use the least squares regression line to make predictions. ... Example 1 (2 minutes): Using a Line to Describe a Relationship ... the model given in the student lesson to predict a man's height using a shoe length of ... Below is a scatter plot of the data with two linear models, ... in Exercise 3 that represents this man

4 0
2 years ago
Suppose that θ is an acute angle of a right triangle and that sec(θ)=52. Find cos(θ) and csc(θ).
insens350 [35]

Answer:

\cos{\theta} = \dfrac{1}{52}

\csc{\theta} = \dfrac{52}{\sqrt{2703}}

Step-by-step explanation:

To solve this question we're going to use trigonometric identities and good ol' Pythagoras theorem.

a) Firstly, sec(θ)=52. we're gonna convert this to cos(θ) using:

\sec{\theta} = \dfrac{1}{\cos{\theta}}

we can substitute the value of sec(θ) in this equation:

52 = \dfrac{1}{\cos{\theta}}

and solve for for cos(θ)

\cos{\theta} = \dfrac{1}{52}

side note: just to confirm we can find the value of θ and verify that is indeed an acute angle by \theta = \arccos{\left(\dfrac{1}{52}\right)} = 88.8^\circ

b) since right triangle is mentioned in the question. We can use:

\cos{\theta} = \dfrac{\text{adj}}{\text{hyp}}

we know the value of cos(θ)=1\52. and by comparing the two. we can say that:

  • length of the adjacent side = 1
  • length of the hypotenuse = 52

we can find the third side using the Pythagoras theorem.

(\text{hyp})^2=(\text{adj})^2+(\text{opp})^2

(52)^2=(1)^2+(\text{opp})^2

\text{opp}=\sqrt{(52)^2-1}

\text{opp}=\sqrt{2703}

  • length of the opposite side = √(2703) ≈ 51.9904

we can find the sin(θ) using this side:

\sin{\theta} = \dfrac{\text{opp}}{\text{hyp}}

\sin{\theta} = \dfrac{\sqrt{2703}}{52}}

and since \csc{\theta} = \dfrac{1}{\sin{\theta}}

\csc{\theta} = \dfrac{52}{\sqrt{2703}}

4 0
3 years ago
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