Determine the value(s) of h such that the matrix is the augmented matrix of a consistent linear system. [Start 2 By 3 Matrix 1s
t Row 1st Column negative 15 2nd Column 21 3rd Column h 2nd Row 1st Column 5 2nd Column negative 7 3rd Column negative 3 EndMatrix ]
1 answer:
Answer: h = 9
Step-by-step explanation: A system of linear equations is consistent when it has at least one solution.
The matrix given is:
Transform this matrix in a row-echelon form:
For this row-echelon form to have solutions:
-9 + h = 0
h = 9
For this system to be consistent: h = 9.
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-7 - 8 - (-8) - 7 × 0(14) - 14 - 30
(I think that's what that says)
Do PEMDAS
0(14) = 0
-7 × 0 = 0
You're left with -7 - 8 - (-8) - 14 - 30
Go from left to right
-7 - 8 = -15
-15 - (-8) = -7
-7 - 14 = -21
-21 - 30 = -51
Could you take a little bit clear picture? :)
Answer:
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Step-by-step explanation:
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16
Step-by-step explanation:
16