Answer:
Option (D) i.e., s1.getClassRank( ); is the correct option to the following question.
Explanation:
Here, in the following option, the object "S1" is the object of the class "rank" and "getClassRank( )" is the function of that class "rank". so, in the following code the function "getClassRank( )" is called through the class object which computes and returns the class rank of the students.
So, that's why the following option is the correct way to call the function.
Answer:
Ctrl + D used to duplicate a slide
All of the aforementioned are true about in-database processing technology except: D. it is the same as in-memory storage technology.
<h3>What is an
in-database processing technology?</h3>
An in-database processing technology can be defined as a type of database technology that is designed and developed to allow the processing of data to be performed within the database, especially by building an analytic logic into the database itself.
This ultimately implies that, an in-database processing technology is completely different from in-memory storage technology because this used for the storage of data.
Read more on database here: brainly.com/question/13179611
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Answer:
Following is the program in C++ Language
#include <iostream> // header file
using namespace std; // namespace std
int main() // main method
{
int n; // variable declaration
cout<<" Please enter the number :";
cin>>n; // Read the number
if(n>0) // check the condition when number is positive
{
cout<<n<<endl<<"The number is Positive"; // Display number
}
else if(n<0) // check the condition when number is Negative
{
cout<<n<<endl<<"The number is Negative";// Display number
}
else // check the condition when number is Zero
{
cout<<n<<endl<<"The number is Zero";// Display number
}
return 0;
}
Output:
Please enter the number:
64
The number is Positive
Explanation:
Following are the description of the program
- Declared a variable "n" of int type.
- Read the value of "n" by user.
- Check the condition of positive number by using if block statement .If n>0 it print the number is positive.
- Check the condition of negative number by using else if block statement If n<0 it print the number is negative.
- Finally if both the above condition is fail it print the message " The number is Zero"
