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Kisachek [45]
2 years ago
10

From the time users first visit a new website, or view a new media piece, how much time will they spend on the site before they

move on?
a- They will spend as little time as possible; people tend to pay little attention to new sites.

b- They will spend as much time as they have; people tend to linger on new websites.

c- They will stay as long as they have to; this is why it is a good idea to “hide” important information.

d- They will stay as long as they are engaged; this is why it is a good idea to make important information easy to find.
Computers and Technology
1 answer:
vesna_86 [32]2 years ago
7 0

Answer:

D

Explanation:

They will stay as long because they want to explore and find out new things on that site and if possible compare with the other sites they have seen

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Assume that the classes listed in the Java Quick Reference have been imported where appropriate.
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The following java code will be written for the prescribed

<u>Explanation:</u>

import java.util.*;

class UserName{

  ArrayList<String> possibleNames;

  UserName(String firstName, String lastName){

      if(this.isValidName(firstName) && this.isValidName(lastName)){

          possibleNames = new ArrayList<String>();

          for(int i=1;i<firstName.length()+1;i++){

              possibleNames.add(lastName+firstName.substring(0,i));

          }  

      }else{

          System.out.println("firstName and lastName must contain letters only.");

      }

  }

  public boolean isUsed(String name, String[] arr){

      for(int i=0;i<arr.length;i++){

          if(name.equals(arr[i]))

              return true;

      }

      return false;

  }

  public void setAvailableUserNames(String[] usedNames){

      String[] names = new String[this.possibleNames.size()];

      names = this.possibleNames.toArray(names);

      for(int i=0;i<usedNames.length;i++){

          if(isUsed(usedNames[i],names)){

              int index = this.possibleNames.indexOf(usedNames[i]);

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              names = this.possibleNames.toArray(names);

          }

      }

  }

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      }

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  }

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      System.out.println("possibleNames after removing: "+person2.possibleNames);

  }

}

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