Perimeter is the outside of it and the perimeter is the inside of it, so I'm pretty sure you would have to do both but if u have to do one then I would go with area
Ok let’s solve it
5(x-2)^2-20=0
first let’s foil (x-2)
5(x^2-4x+4) -20=0
now distribute the 5
5x^2 -20x +20 -20 = 0
combine like terms
5x^2-20x=0
take the gcf
5x(x-4)=0
x=0, 4
solutions are (4,0) and (2, -20) because the original vertex form a(x-h)^2+k
F(-4)= 9*3^(-4)=9/(3^4)=1/9
Answer:
1) -10
2) 1
Step-by-step explanation:
1) (-5) - 5
- Removing the brackets won't change anything since it is subtraction, so now it will be - 5-5 which is equal to -10.
-5 -5 = -10
2) (-10) + 11
- The same case applies here since it is addition.
-10 + 11 = 1
