Here, we are required to find the equation, in terms of w, that could be used to find the dimensions of the storage unit in feet.
The polynomial is;. 3w³ + 22w + 24w = 5440ft³.
From the question;
- <em>Let the width = w</em>
- <em>length,</em><em> </em><em>l</em><em> = 3w + 4</em>
- <em>height,</em><em> </em><em>h</em><em> = w + 6</em>
<em>The </em><em>volume </em><em>of </em><em>a </em><em>rectangular</em><em> </em><em>prism </em><em>is </em><em>given </em><em>by </em><em>the </em><em>product </em><em>of </em><em>its </em><em>length,</em><em> </em><em>width </em><em>and </em><em>height.</em><em> </em><em>Thus</em><em>;</em>
Volume = l × w × h
Therefore, Volume, V = (3w +4) × w × (w +6)
To obtain the required polynomial, we expand the expression for Volume above;
<em>V = (3w² + 4w) × (w + 6)</em>
<em>V = (3w² + 4w) × (w + 6)V = 3w³ + 22w² + 24w.</em>
However, the volume of the rectangular prism has been given to be 5440 cubic feet.
Therefore, the polynomial is;
3w³ + 22w + 24w = 5440ft³.
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Answer:
E. x^2 = 39 + 10x
Step-by-step explanation:
It helps to do one piece of the sentence at a time.
"A number, x, squared is 39 more than the product of 10 and x"
x
"A number, x, squared is 39 more than the product of 10 and x"
x^2 =
"A number, x, squared is 39 more than the product of 10 and x"
x^2 = 39 +
"A number, x, squared is 39 more than the product of 10 and x"
x^2 = 39 + 10x
Answer: E. x^2 = 39 + 10x
Answer: 1
Step-by-step explanation:
3x + 8x-8= 3
11x-8=3
Then you move the 8 to the other side and change it to a positive.
11x= 11
11x/11 = 11/11
Answer is 1
Answer:
Option (4)
Step-by-step explanation:
Area of the figure given in the picture = Area of large rectangle - Area of rectangle A
Area of rectangle A = Length × Width
= [9 - (2 + 4)] × 3
= 3 × 3
= 9
Area of the large rectangle = Length × Width
= 9 × 5
= 45
Therefore, area of the given figure = 45 - 9
= 36
Option (4) will be the correct option.
<h3>
Answer: 24 (choice C)</h3>
Assuming M is a midpoint of KW, this means that WM and KM are congruent
WM = KM
x+3 = 2(x-3) ... substitution
x+3 = 2x-6
2x-6 = x+3
2x-6-x = x+3-x .... subtract x from both sides
x-6 = 3
x-6+6 = 3+6 ... add 6 to both sides
x = 9
Use x = 9 to find the length of WM
WM = x+3 = 9+3 = 12
Which can be used to find the length of KM as well
KM = 2(x-3) = 2(9-3) = 2(6) = 12
both lengths are the same (12) as expected
This makes WK to be
WK = WM + KM
WK = 12 + 12
WK = 24
