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Murljashka [212]

3 years ago

13

PLEASE HELP!!! THERE IS A PICTURE ATTACHED

2 answers:

Lunna [17]3 years ago

6 0

Answer:

Step-by-step explanation:

ample Response: The events are dependent, so the sample space changes for the second draw. After drawing the first marble, there are only 11 marbles left. The probability is (

2

12

) (

4

11

) =

8

132

, or

2

33

.

telo118 [61]3 years ago

4 0

Well, the problem is that he does not replace the first marble after he draws it. Therefore, yes, he has a 2/12 probability of drawing a yellow marble first, but then he has a 4/11 probability of drawing a red marble second, not 4/12. This is because there are going to only be 11 marbles left in the bag after he draws the first marble and does not replace it.

The correct answer would be:
(2/12)(4/11)=8/132=4/66=2/33

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Answer:

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Step-by-step explanation:

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OLEGan [10]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The line is $y = -4 x$

Step-by-step explanation:

From the question we are told that

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Answer:

Step-by-step explanation:

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Dahasolnce [82]

Answer:

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Step-by-step explanation:

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4 0

3 years ago

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