We have the following function:
f (x) = 2a ^ 2b + 3a ^ 3b ^ 2 + 2a ^ 2b ^ 4
We note that the function depends on x because it is f (x).
However, there is no variable x in the function.
Therefore we can assume that the function is constant, since:
a = constant
b = constant
Therefore, the degree of the function is zero
Answer:
The function is zero degree.
Answer:
3n + 2
Step-by-step explanation:
-n+(-4)-(-4n)+6
= -n -4 +4n +6 [positive plus negative = negative; ∴ +(-4) = -4
=4n - n +6 - 4 negative plus negative = positive; ∴ -(-4n) = 4]
now subtract n from 4n and subtract 4 from 6
=3n + 2
Y = mx + b. This linear graph passes through A(0,50) and B(10,51)
m = (y₂-y₁)/(x₂-x₁)
m= (51-50)/10-0)
m=(1)(10)
y = (1/x) + b. To find b, you plugin the coordinates of either A or B,
say A(0,50):
50 = (1/10).(0) + b
50 = 0+b and b= 51
Hence the equation is y =0.1x + 50
Answer:n=-83/60 or -1.383
Step-by-step explanation:
Factors of 35: 1, 5, 7, 35
Of those, only 5 and 7 are prime.
7>5
Final answer: 7
