Answer: N(t) = (2^t)*1500
Step-by-step explanation:
Let's define the hour "zero" as the initial population.
So if N(t) is the number of bacteria after t hours, then:
N(0) = 1500.
Now, we know that the population doubles every hour, so we will have that after one hour, at t = 1
N(1) = 2*1500 = 3000
after two hours, at t = 2.
N(2) = 2*(2*1500) = (2^2)*1500
After three hours, at t = 3
N(3) = 2*(2^2)*1500 = (2^3)*1500
So we already can see the pattern, the number of bacteria after t hours will be:
N(t) = (2^t)*1500
3 to the 4th power = 3x3x3x3 which is 81 :)
To find what the number is, we need to set up proportional fractions.
Currently, we have 8% of a number is 20.
To set up our fractions, put 100% under 8% as a fraction first.
It should look like this: 8/100 (hint: per-cent means per-hundred).
Now, we have 20 out of a number, x. This is because we are claiming that 20 is 8% of a number (if we just reword the question without changing the concept).
It should look like this: 20/x.
Our proportional fractions are:
20/x = 8/100.
To solve for this, we need to cross-multiply the denominator of 8/100 (bottom number, 100) with the numerator of 20/x (top number, 20).
This product equation should look like this:
20 x 100 (when simplified, we get 2000).
Now, we need to cross multiply the numerator of 8/100 (top number, 8) with the denominator of 20/x (bottom number, x).
This product equation should look like this:
8x.
Now that we've cross-multiplied, set our two products as an equation.
8x = 2000.
To solve for x, divide both sides by 8 (remember, what you do to one side of an equation, you must do it to the other).
8x / 8 = x
2000 / 8 = 250.
x = 250
Your final answer is:
8% of 250 is 20.
I hope this helps!
Answer:
<h2>
C. 533.8 ft. squared</h2>
Step-by-step explanation:
Depending on the Pi that you use, the answer should be fairly close, for this I used the full Pi in the equation and got about 534.07 and answer C is closest to that answer so C is the best option.
Hope this helps! Have a good day/night!
To find conjecture about regular polygon, use the formula
Where, n = number of sides of the regular polygone
1) Triangle
n =3
So, Conjecture of the triangle =
= 120
2) Square
n =4
So, Conjecture of the square =
= 90
3) Pentagone
n = 5
So, Conjecture of the pentagon =
= 72
4) Hexagone
n = 6
So, Conjecture of the pentagon =
= 60.
