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insens350 [35]
3 years ago
14

How many sides are there on a convex polygon if the sum of the interior angles is 3240?

Mathematics
1 answer:
natta225 [31]3 years ago
8 0
Pretty sure 20 sorry if not right
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Use the remainder theorem to determine if x=6 is a zero of the following polynomial, and find the quotient and the remainder.
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I think your answer is C correct me if I’m wrong
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You offer senior citizens a 20% discount on their tune-ups at your gas station. Assuming that an average of 50 senior citizens g
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X over 49.5 and 20 over 100 then you cross multiply and you get 100x is equal to 990 you divide 100x and 990 both by 100 and get x and 9.9 then you have 50 seniors a month that you give the discount to so you multiply 9.9 by 50 and get 495 so the total discount you give on an average monthly basis is $495.00 Hope this helped
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3 years ago
U= {1,2,3,4,5,6,7,8,}, A={1,4,5,7}, B= {2,5,6,7,}, and C= {3,4,6,7}
choli [55]

Answer:

  a. {1, 2, 3, 4, 5, 6, 7}

  b. {1, 2, 3, 4, 5, 6, 8}

  c. {4, 5, 7}

  d. {1, 4, 5}

Step-by-step explanation:

The union of two sets is the list of elements in either set. The intersection of two sets is the list of elements in both sets. The complement of a set is the list of elements in the universal set that are not in the set being complemented. The complement of a set can be indicated with an apostrophe: A' is the complement of set A, for example.

<h3>a. AU(BUC)</h3>

B∪C = {2, 5, 6, 7} ∪ {3, 4, 6, 7} = {2, 3, 4, 5, 6, 7}

A∪(B∪C) = {1, 4, 5, 7} ∪ {2, 3, 4, 5, 6, 7} = {1, 2, 3, 4, 5, 6, 7}

<h3>b. (AN(BNC))'</h3>

B∩C = {2, 5, 6, 7} ∩ {3, 4, 6, 7} = {6, 7}

A ∩ (B∩C) = {1, 4, 5, 7} ∩ {6, 7} = {7}

(A∩(B∩C))' = {7}' = {1, 2, 3, 4, 5, 6, 8}

<h3>c. (ANB)U(ANC)</h3>

A∩Β = {1, 4, 5, 7} ∩ {2, 5, 6, 7} = {5, 7}

Α∩C = {1, 4, 5, 7} ∩ {3, 4, 6, 7} = {4, 7}

(A∩B)∪(A∩C) = {5, 7} ∪ {4, 7} = {4, 5, 7}

<h3>d. (ANB')U(ANC')</h3>

(A∩B')∪(A∩C') = A∩(B'∪C') = A∩(B∩C)'

(B∩C)' = {6, 7}' = {1, 2, 3, 4, 5, 8}

A∩(B∩C)' = {1, 4, 5, 7} ∩ {1, 2, 3, 4, 5, 8} = {1, 4, 5}

__

<em>Additional comment</em>

In part (d) we made use of De Morgan's law for sets:

  B'∪C' = (B∩C)'

We also made use of the distributive property for sets:

  A∩(B∪C) = (A∩B)∪(A∩C)

6 0
2 years ago
I WILL MARK BRAINIEST IF ANSWERED RIGHT AND ASAP
iogann1982 [59]
A 1 over 32 square foot
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Use the number line to add the fraction. A number line ranging from negative 1 and 3 tenths to positive 9 tenths Drag and drop t
Lunna [17]

Answer:

1/10

Step-by-step explanation:

1

Find the Least Common Denominator (LCD) of 25,12\frac{2}{5}, \frac{1}{2}​5​​2​​,​2​​1​​.

Method 1: By Listing Multiples

List out all multiples of each denominator, and find the first common one.

Multiples of 5

: 5, 10, ...

Multiples of 2

: 2, 4, 6, 8, 10, ...

Therefore, the LCD is 101010.

Method 2: By Prime Factors

Since 5,25,25,2 are prime numbers themselves, we simply multiply them to get the LCD.

Therefore, the LCD is 5×2=105\times 2=105×2=10.

LCD = 101010

2

Make the denominators the same as the LCD.

−2×25×2+1×52×5-\frac{2\times 2}{5\times 2}+\frac{1\times 5}{2\times 5}−​5×2​​2×2​​+​2×5​​1×5​​

3

Simplify. Denominators are now the same.

−410+510-\frac{4}{10}+\frac{5}{10}−​10​​4​​+​10​​5​​

4

Join the denominators.

−4+510\frac{-4+5}{10}​10​​−4+5​​

5

Simplify.

110\frac{1}{10}​10​​1​​

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3 years ago
Read 2 more answers
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