Hello!!
For calculate the work let's applicate the formula:
W = Work = ?
F = Force = 1525 N
d = Distance = 381 m
⇒
W = 1525 N * 381 m
⇒
W = 581025 J
Answer:
i) C decreases
ii) Q remains constant
iii) E remains constant
iv) ΔV increases
Explanation:
i)
We know, capacitance is given by:
<em>In this case as the distance between the plates increases the capacitance decreases while area and permittivity of free space remains constant.</em>
ii)
As the amount of charge has nothing to do with the plate separation in case of an open circuit hence the charge Q remains constant.
iii)
Electric field between the plates is given as:
where:
charge density,
<em>As we know that distance of plate separation cannot affect area of the plate. Charge Q and permittivity are also not affected by it, so E remains constant.</em>
iv)
- From the basic definition of voltage we know that it is the work done per unit charge to move it through a distance.
- Here we increase the distance so the work done per unit charge increases.
The outlier is 150
mean with the outlier: around 29.57
median with the outlier: 10
mean without the outlier: 9.5
median without the outlier: 8.5