Answer: = 5.75 × 10 -6
Explanation:
= 5.75 × 10-6
(scientific notation)
= 5.75e-6
(scientific e notation)
= 5.75 × 10-6
(engineering notation)
(millionth; prefix micro- (u))
= 0.00000575
(real number)
Use this formula to find your answer...
Determine the frequency of a clock waveform whose period is 2us or (micro) and 0.75ms
frequency (f)=1/( Time period).
Frequency of 2 us clock =1/2*10^-6 =10^6/2 =500000Hz =500 kHz.
Frequency of 0..75ms clock =1/0.75*10^-3 =10^3/0.75 =1333.33Hz =1.33kHz.
Answer:
![v_f=-0.29\frac{m}{s}](https://tex.z-dn.net/?f=v_f%3D-0.29%5Cfrac%7Bm%7D%7Bs%7D)
Explanation:
The principle of conservation of momentum, states that if the sum of the forces acting on a system is null, the initial total momentum of the system before a collision equals the final total momentum of the system after the collision. The collision is completely inelastic, which means that the players remain stick to each other after the collision:
![p_i=p_f\\m_1v_1+m_2v_2=(m_1+m_2)v_f\\v_f=\frac{m_1v_1+m_2v_2}{(m_1+m_2)}\\\\v_f=\frac{(110kg)4.5\frac{m}{s}+150kg(-3.8\frac{m}{s})}{(110kg+150kg)}\\v_f=-0.29\frac{m}{s}](https://tex.z-dn.net/?f=p_i%3Dp_f%5C%5Cm_1v_1%2Bm_2v_2%3D%28m_1%2Bm_2%29v_f%5C%5Cv_f%3D%5Cfrac%7Bm_1v_1%2Bm_2v_2%7D%7B%28m_1%2Bm_2%29%7D%5C%5C%5C%5Cv_f%3D%5Cfrac%7B%28110kg%294.5%5Cfrac%7Bm%7D%7Bs%7D%2B150kg%28-3.8%5Cfrac%7Bm%7D%7Bs%7D%29%7D%7B%28110kg%2B150kg%29%7D%5C%5Cv_f%3D-0.29%5Cfrac%7Bm%7D%7Bs%7D)
Explanation:
doesn’t corrode easily and is soft enough for inexpensive tools to cut to the needed individual patterns.
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