Answer:
They use noise control, creating a wave that negates outside or ambient sound and replaces it with the desired sound that listeners request.
Explanation:
I hope this helped
Answer:
c. initial (x and y)
Explanation:
When a projectile is launched at a velocity with a launch angle, to solve it, we must first resolve the initial velocity into the x and y components. To do this will mean we have to treat it like a triangle due to the launch angle and the direction of the projectile.
Therefore, we will have to make use of trigonometric ratios which is also known by the mnemonic "SOH CAH TOA"
Thus, this method resolves the initial x and y velocities.
Answer:
230 m/s northeast, 1.8 m/s up
Explanation:
204 kilometres = 204000 metres
15.0 minutes = 900 seconds
Velocity = Distance / Time
= 204000 / 900
= 230 m/s northeast (to 2 sf.)
1.6km = 1600 metres
Velocity = 1600 / 900
= 1.8 m/s up (to 2 sf.)
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Answer:
P = 5sin(880πt)
Explanation:
We write the pressure in the form P = Asin2πft where A = amplitude of pressure, f = frequency of vibration and t = time.
Now, striking the middle-A tuning fork with a force that produces a maximum pressure of 5 pascals implies A = 5 Pa.
Also, the frequency of vibration is 440 hertz. So, f = 440Hz
Thus, P = Asin2πft
P = 5sin2π(440)t
P = 5sin(880πt)
