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luda_lava [24]
1 year ago
7

A 500 N person stands on a unifrom board of weight 100 N and length 8.0 m. The board is supported at each end. If the support fo

rce at the right end is three times that at the left end, how far from the right end is the person
Physics
1 answer:
loris [4]1 year ago
5 0

Answer:

The far from the right end is the person was 1.6

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A flea jumps straight up to a maximum height of 0.540 m . what is its initial velocity v0 as it leaves the ground?
jok3333 [9.3K]
For an uniformly accelerated motion, we can write
2ah=v_f^2-v_0^2
where a=g=-9.81 m/s^2 is the acceleration of this motion, which in this problem is the gravitational acceleration, with a negative sign because it points downward, against the direction of the motion; h=0.540 m is the distance covered by the flea, and v_0 is the initial velocity. 

At the maximum height, the velocity is zero, so v_f =0. Therefore we  can solve to find v_0:
v_0 =  \sqrt{2ah}= \sqrt{2(9.81 m/s^2)(0.540 m)}  =3.25 m/s
3 0
3 years ago
Which one of the following statements does not accurately describe vibrations?
Paladinen [302]
A. Forced vibrations, such as those between a tuning fork and a large cabinet surface, result in a much lower sound than was produced by the original vibrating body.
4 0
3 years ago
Why does conduction occur in solids?
dmitriy555 [2]

Answer:

Conduction occurs more readily in solids and liquids, where the particles are closer to together, than in gases, where particles are further apart. ... As these molecules collide, thermal energy is transferred via conduction to the rest of the pan.

Explanation:

Metals have tightly packed atoms which can easily pass on their kinetic energy and also have free moving electrons.

5 0
3 years ago
Convert 13.1 miles to feet. Using one step conversion
Marat540 [252]

Answer:

69,168 ft

Explanation:

6 0
3 years ago
A solid 200-g block of lead and a solid 200-g block of copper are completely submerged in an aquarium filled with water. Each bl
finlep [7]

Answer:

B. The buoyant force on the copper block is greater than the buoyant force on the lead block.

Explanation:

Given;

mass of lead block, m₁ = 200 g = 0.2 kg

mass of copper block, m₂ = 200 g = 0.2 kg

density of water, ρ = 1 g/cm³

density of lead block, ρ₁ = 11.34 g/cm³

density of copper block, ρ₂ = 8.96 g/cm³

The buoyant force on each block is calculated as;

F_B = mg(\frac{density \ of \ fluid}{density \ of \ object} )

The buoyant force of lead block;

F_{lead} = 0.2*9.8(\frac{1}{11.34} )\\\\F_{lead} = 0.173  \ N

The buoyant force of copper block

F_{copper} = 0.2*9.8(\frac{1}{8.96})\\\\F_{copper} = 0.219  \ N

Therefore, the buoyant force on the copper block is greater than the buoyant force on the lead block

3 0
3 years ago
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