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4 years ago

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We are sending a 30 Mbit file from source host A to destination host B. All links in the path between source and destination hav

e a transmission rate of 10 Mbps. Assume that the propagation speed is 2 *10^8 meters/sec, and the distance between source and destination is 10,000 km. The end-to-end delay (transmission delay plus propagation delay) is:

1 answer:

Dmitrij [34]4 years ago

3 0

Answer:

$t=1.5\times 10^{-4}\ s$

Explanation:

Given:

file size to be transmitted, $D=30\ Mb$

transmission rate of data, $\dot D=10\ Mb.s^{-1}$

propagation speed, $v=2\times 10^8\ m.s^{-1}$

distance of data transfer, $s=10000\ km=10^4\ m$

<u>Now the delay in data transfer from source to destination for each 10 Mb:</u>

$t'=\frac{s}{v}$

$t'=\frac{10^4}{2\times 10^8}$

$t'=5\times 10^{-5}\ s$

<u>Now this time is taken for each 10 Mb of data transfer and we have 30 Mb to transfer:</u>

So,

$t=3\times t'$

$t=3\times 5\times 10^{-5}$

$t=1.5\times 10^{-4}\ s$

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slavikrds [6]

Answer:

Correct option A.

The net force exerted by this loop on the straight wire with the current is directed TOWARDS THE LOOP

Explanation:

The magnetic field exerts a force on a current-carrying wire in a direction given by the right-hand rule 1 (the same direction as that on the individual moving charges). This force can easily be large enough to move the wire since typical currents consist of very large numbers of moving charges.

Given that,

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Since the 'dot' field is increasing hence the induced magnetic field is 'cross', i.e. into the page and by the right-hand rule, the induced current is clockwise.

Then the magnetic field is into the page.

Since was known that

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So using right hand rule,

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4 years ago

An object is moving with an initial velocity of 19 m/s.It is then subject to a constant acceleration of 2.5 m/s for 15s.How far

bija089 [108]

Answer:

566.3 m

Explanation:

The distance travelled by the object can be found by using the SUVAT equation:

$d=ut+\frac{1}{2}at^2$

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a is the acceleration

For the object in this problem:

u = 19 m/s

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4 years ago

If a 3-kg object has a momentum of 33 kgÂ·m/s, what's its velocity?

Eddi Din [679]

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3 years ago

An electron is released from rest at the negative plate of a parallel plate capacitor. The charge per unit area on each plate is

amm1812

Answer: $1.066\times 10^7 m/s$

Explanation:

Given

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3 years ago

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bekas [8.4K]

<h3><u>Answer;</u></h3>

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4 years ago