Answer:
20 m/s
30 m/s
Explanation:
Given:
v₀ = -10 m/s
a = -9.8 m/s²
When t = 1 s:
v = v₀ + at
v = (-10 m/s) + (-9.8 m/s²) (1 s)
v = -19.8 m/s
When t = 2 s:
v = v₀ + at
v = (-10 m/s) + (-9.8 m/s²) (2 s)
v = -29.6 m/s
Rounded to one significant figures, the speed of the ball at 1 s and 2 s is 20 m/s and 30 m/s, respectively.
The force is still 1 pound.
The TORQUE around the pivot is (force) x (distance from the pivot) = 1 foot-pound. (B)
The answer is: [D]: "the position of the moon each month in relation to THE SUN AND THE MOON" .
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Note of interest: The origin of the word "month" was: "moon-th" — but shortened to "month" — (no coincidence!).
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Answer:
The force needed will be greater to hold the object at rest.
Explanation:
For a better understanding let's take a look at the attached image.
In the image there is an example of this condition, we have an object of 3 kg-f mass, the first angle between the horizontal and the inclined plane is 35°. When we increase the angle to 45°. We can realize that we need to hold the object with a stronger force.
The calculation and the equations based on Newton's laws can be found in the attached image.