Answer:
a)
, b) 
Explanation:
a) The heat transfered to the egg is computed by the First Law of Thermodynamics:





b) The amount of entropy generation is determined by the Second Law of Thermodynamics:



Answer:
Well a s the temperature increases, at a certain point called the Curie temperature, a magnet will lose its strength completely. So once the metal cools, its ability to attract magnets returns, though its permanent magnetism becomes weak. In general heat is the factor that has the most effect on permanent magnets.Explanation:
I don’t think so because an ice cube melting needs heat and relies on temp while ooblecks transition from solid to quickly depends on force and speed
Answer:

Explanation:
From the exercise we have:

To find the velocity after 2.4s we need to use the following formula:


The negative sign means that the kit is going down.
Answer:
The speed of light (c)
Explanation:
The equation that relates the magnetic field component of an electromagnetic wave the the electric field component of the wave is:

where
E is the magnitude of the electric field component
B is the magnitude of the magnetic field component
c is the speed of light in a vacuum, whose value is

Re-arranging the equation to solve for B, we find:
