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Setler [38]
3 years ago
7

Whoever answers correctly gets BRAINLIEST and 100 points

Mathematics
1 answer:
12345 [234]3 years ago
3 0

Answer:

\sf 59 \frac{17}{20} \: in^3

Step-by-step explanation:

<u>Regular-size box of crackers</u>

Dimensions:  \sf 2 \frac{1}{4} \: in \times 9 \frac{1}{2}\:in \times 14\: in

<u>Snack-size box of crackers</u>

Volume = \sf \frac{1}{5} of the volume of a regular-size box

To calculate the <u>volume of the snack-size box</u> of crackers, calculate the volume of the regular-size box then multiply it by \sf \frac{1}{5}.

\begin{aligned}\textsf{Volume of a rectangular prism} & = \textsf{width x length x height}\\\\\implies \textsf{Volume of regular-size box} & = \sf 9 \frac{1}{2} \times 14 \times 2 \frac{1}{4}\\\\& = \sf \dfrac{19}{2} \times 14 \times \dfrac{9}{4}\\\\& = \sf \dfrac{19 \times 14 \times 9}{2 \times 4}\\\\& = \sf \dfrac{1197}{4}\: in^3\end{aligned}

\begin{aligned}\implies \textsf{Volume of snack-size box} & = \sf \dfrac{1}{5} \times \textsf{volume of regular-size box}\\\\& = \sf \dfrac{1}{5} \times \dfrac{1197}{4}\\\\& = \sf \dfrac{1 \times 1197}{5 \times 4}\\\\& = \sf \dfrac{1197}{20}\\\\& = \sf 59 \dfrac{17}{20}\: in^3\end{aligned}

Therefore, the volume of the snack-size box is \sf 59 \frac{17}{20} \: in^3

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Suppose a national survey conducted among a simple random sample of 1475 adults shows that 54% of Americans think the Civil War
Lorico [155]

Answer:

(1) H_0 : p = 0.5, H_A : p > 0.5

(2) Test statistic = 3.08

(3) P-value = 0.00104

Step-by-step explanation:

We are given that a simple random sample of 1475 adults shows that 54% of Americans think the Civil War is still relevant to American politics and political life.

We have to test the hypothesis to determine if there is a strong evidence that the majority of the Americans think the Civil War is still relevant.

(1) Let Null Hypothesis, H_0 : p = 0.50  {means that 50% of the Americans think that the Civil War is still relevant}

Alternate Hypothesis, H_a : p > 0.50  {means that majority of the Americans think that the Civil War is still relevant,i.e; more than 50%}

The test statistics that will be used here is One-sample proportion test;

              T.S. = \frac{\hat p -p}{\sqrt{\frac{\hat p(1-\hat p)}{n} }   } ~ N(0,1)

where, \hat p = % of Americans who think that the Civil War is still relevant in a sample of 1475 adults = 54%

           p = population proportion

           n = sample of american adults = 1475

(2) So, <u>test statistics</u>  =  \frac{0.54-0.50}{\sqrt{\frac{0.54(1-0.54)}{1475} }   }

                                    = 3.08

The value of test statistic for this hypothesis test is 3.08.

(3) P-value is given by the following situation;

           P(Z > 3.08) = 1 - P(Z \leq 3.08)                {using z table}

                              = 1 - 0.99896 = 0.00104

So, the p-value for this hypothesis test is 0.00104.

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let x be the number

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