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mars1129 [50]
3 years ago
11

If you kick a ball and the ball accelerates through the air, the forces involved must be

Physics
1 answer:
wariber [46]3 years ago
7 0
It would be kinetic and potential energy, potential from the force of the kick, and kinetic from energy exerted.
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State the<br>the properties of magnets.<br>​
Zigmanuir [339]

Answer:

All magnets have two poles: the North Pole and the South Pole.

Magnets attract ferromagnetic materials such as iron, nickel, and cobalt.

The magnetic force of a magnet is stronger at its poles than in the middle.

A freely suspended magnet always points in North-South direction.

Hope this helps

4 0
3 years ago
A charged particle moving through a magnetic field at right angles to the field with a speed of 24.7 m/s experiences a magnetic
Sunny_sXe [5.5K]

Answer:

Explanation:

let the charge is q. velocity, v = 24.7 m/s

magnetic force, F = 2.38 x 10^-4 N

Let the magnetic field is B.

Velocity, v' = 5.64 m/s

angle, θ = 21.2°

The force experienced by a charged particle placed in a magnetic field is given by

F = q x v x B x Sinθ

in first case

2.38 x 10^-4 = q x 24.7 x B x Sin 90 .... (1)

in second case

F = q x 5.64 x B x Sin 21.2°      .... (2)

Divide equation (2) by equation (1), we get

\frac{F}{2.38\times 10^{-4}}=\frac{5.64\times Sin 21.2}{24.7\times Sin 90}

F = 1.97 x 10^-5 N

7 0
4 years ago
Two billiard balls of identical mass move toward each other. Assume that the collision between them is perfectly elastic. If the
anzhelika [568]

Answer:

-20.0 m/s and 30.0 m/s

Explanation:

Momentum is conserved:

m (30.0) + m (-20.0) = m v₁ + m v₂

30.0 − 20.0 = v₁ + v₂

10.0 = v₁ + v₂

Since the collision is perfectly elastic, energy is also conserved.  Since there's no rotational energy or work done by friction, the initial kinetic energy equals the final kinetic energy.

½ m (30.0)² + ½ m (-20.0)² = ½ mv₁² + ½ mv₂²

(30.0)² + (-20.0)² = v₁² + v₂²

1300 = v₁² + v₂²

We now have two equations and two variables.  Solve the system of equations using substitution:

1300 = v₁² + (10 − v₁)²

1300 = v₁² + 100 − 20v₁ + v₁²

0 = 2v₁² − 20v₁ − 1200

0 = v₁² − 10v₁ − 600

0 = (v₁ + 20) (v₁ − 30)

v₁ = -20, 30

If v₁ = -20, v₂ = 30.

If v₁ = 30, v₂ = -20.

So either way, the final velocities are -20.0 m/s and 30.0 m/s.

3 0
3 years ago
Read 2 more answers
Two slits separated by a distance of d = 0.190 mm are located at a distance of D = 1.91 m from a screen. The screen is oriented
Svetlanka [38]

Answer:

\theta = 0.195^0

Explanation:

wavelength \lambda  = 648 nm \   = 648*10^{-9}m

d = 0.190 mm = 0.190 × 10⁻³ m

D = 1.91 m

By using the formula:

dsin \theta = n \lambda\\\\\theta = sin^{(-1)}(\frac{n \lambda}{d})\\\\\\\theta = sin^{(-1)}(\frac{1*648*10^{-9}}{0.190*10^{-3}})

\theta = 0.195^0

The first maximum will appear at an angle \theta = 0.195^0 from the beam axis

3 0
3 years ago
What part of the rocket reaches space?
Romashka-Z-Leto [24]
All of it until it breaks down into 1 piece

7 0
4 years ago
Read 2 more answers
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