1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
laiz [17]
4 years ago
14

“How bright would the sun appear to an observer on Earth if the sun were four times farther from Earth than it actually is? Expr

ess your answer as a fraction of the sun’s brightness on Earth’s surface.”
Physics
1 answer:
Alenkasestr [34]4 years ago
4 0

Like a lot of other things, (gravity, sound, electrostatic force), brightness also decreases as the square of the distance.

When the source moves to a new position that's 4 times as far away, its apparent brightness becomes (1/4^2) its original value.

That's 1/16 .

You might be interested in
A person drives to the top of a mountain. On the way up, the person’s ears fail to “pop,” or equalize the pressure of the inner
KATRIN_1 [288]
The pressure on the inner ear is calculated by subtracting the pressure of the atmosphere of the bottom from the top, so calculating this will give us: 1.010x10^5 - .998x10^5 = 1200Pa outward which would be letter A.
And so the net force would be now calculated as P*A = 1200Pa*π*(0.40x10^-2m)^2 = 0.0603N
3 0
3 years ago
he coefficent of static friction between the floor of atruck and a box resting on it is 0.30. The truck is travelingat 80.0 km/h
Vedmedyk [2.9K]

Answer:

83.97 m

Explanation:

Without any other external force causing motion in the horizontal direction, it is the frictional force that brings the box to rest. The frictional force has to match the force due to deceleration experienced by the truck to not move.

So,

Frictional force = ma

Then, we calculate frictional force now,

In the vertical direction, the force balance has the weight and the normal reaction equal

N = W = mg

And frictional force = μN = μmg

where μ is the coefficient of friction = 0.3

ma = μmg

a = μg = 0.3 × 9.8 = 2.94 m/s²

Then, using the equations of motion, we obtain the distance over which this deceleration stops the truck

u = initial velocity of the truck = 80 km/h = 22.22 m/s

v = final velocity of the truck = 0 m/s, since the truck comes to rest

a = - 2.94 m/s² (negative sign because it's a deceleration)

x = distance covered during this deceleration = ?

v² = u² + 2ax

0² = 22.22² + 2(-2.94)(x)

5.88x = 493.73

x = 83.97 m

4 0
3 years ago
Read 2 more answers
If a seagull drops a shell from rest at a height of 12 m how fast is the shell moving when it hits the rocks
Dvinal [7]

As seagull drops a shell from rest at a height of 12 m, so we use kinematic equation of motion,

v^{2} = u^{2} +2g h

Here, h is the height, u is initial velocity , v is final velocity and g is acceleration due to gravity.

Given,  h = 12 m.

We take, g = 9.8 \ m/s^2 and u = 0 because seagull drops a  shell from rest.

Therefore, the speed of shell when it hits the rocks,

v^{2} = 0 + 2 \times 9.8 m/s^2 \times 12 \ m = 235.2 (m/s)^2 \\\\ v = \sqrt{235.2 (m/s)^2} = 15.33 \ m/s^2

5 0
3 years ago
. Alpha-emitting substances, such as radon gas, can be a serious health hazard only if _____. their radiation strikes the skin t
Masja [62]

Answer:Answer:

They are inhaled or eaten

Explanation:

Radioactivity can be defined as the process in which an unstable atomic nucleus spontaneously emits ionizing radiation and charge particles. This eventually results in the formation of an energetically stable atomic nucleus.

Examples of radioactive elements are Uranium, Polonium, Thorium, Radon, etc. The radiation emitted during this process is classified as;

1. Alpha radiation (α).

2. Beta radiation (β).

3. Gamma radiation (G).

Alpha-emitting substances, such as radon gas, can be a serious health hazard only if they are inhaled or eaten. Alpha-emitting substances compared to other radiation has very short-range particle and as such cannot penetrate the human skin or body.

8 0
3 years ago
Find the average braking force of a 1000 kg car moving at 10 m/s braking to a stop in 5 s.
Verdich [7]

Answer:

-2000 N

Explanation:

To solve the problem, we can use the impulse theorem, which states that the impulse is equal to the change in momentum of the car:

I = \Delta p\\F \Delta t = m \Delta v

where

F is the average breaking force

\Delta t = 5 s is the stopping time

m = 1000 kg is the mass of the car

\Delta v = -10 m/s is the change in velocity of the car

Solving the equation for F,

F=\frac{m \Delta v}{\Delta t}=\frac{(1000 kg)(-10 m/s)}{5 s}=-2000 N

5 0
4 years ago
Other questions:
  • Cole and Blayne were attempting to push Hailey on a wheeled chair with enough force so Hailey would run into Mr Young. They figu
    5·2 answers
  • What is the best inference for the height of the plant after 35 hours?
    15·1 answer
  • Divide 0.0081 meters by 300 seconds and express the answer in scientific notation.
    11·2 answers
  • What does Archimedes' principle say about how the buoyant force relates to the fluid involved?
    11·1 answer
  • It is claimed that if a lead bullet goes fast enough, it can melt completely when it comes to a halt suddenly, and all its kinet
    7·1 answer
  • WILL GIVE BRAINIEST AWARD TO CORRECT
    11·2 answers
  • Which item stores the most electrical potential energy within its capacitors?
    6·1 answer
  • A train car, which has a mass of 2000 kg, is rolling along with a velocity of 20 m/s East. It
    6·1 answer
  • What is the x component of a vector that is defined as<br> 45m at -35°?
    11·1 answer
  • What happens to the force between two objects if the mass of one object is doubled.
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!