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laiz [17]
3 years ago
14

“How bright would the sun appear to an observer on Earth if the sun were four times farther from Earth than it actually is? Expr

ess your answer as a fraction of the sun’s brightness on Earth’s surface.”
Physics
1 answer:
Alenkasestr [34]3 years ago
4 0

Like a lot of other things, (gravity, sound, electrostatic force), brightness also decreases as the square of the distance.

When the source moves to a new position that's 4 times as far away, its apparent brightness becomes (1/4^2) its original value.

That's 1/16 .

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The light will bend when in 
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14. A rocket is shot up into the air and then comes back down and hits the ground 9.2 second later.
sineoko [7]

Answer:

105.8 m

46 m/s

Explanation:

From the time the rocket is launched to the time it reaches its maximum height:

v = 0 m/s

a = -10 m/s²

t = 9.2 s / 2 = 4.6 s

Find: Δy and v₀

Δy = vt − ½ at²

Δy = (0 m/s) (4.6 s) − ½ (-10 m/s²) (4.6 s)²

Δy = 105.8 m

v = at + v₀

0 m/s = (-10 m/s²) (4.6 s) + v₀

v₀ = 46 m/s

3 0
4 years ago
An acorn falls from a tree and hits the ground in 0.8 s. How far did the acorn fall . Use g = 9.8 m/s^2. Round your final result
mylen [45]

The distance covered by the acorn is 3.136 m.

<u>Explanation:</u>

The time taken for the acorn to hit the ground is 0.8 s. As it is a free fall, the acorn will be completely under the influence of gravity. So the acceleration will be acceleration due to gravity.

Then using the second law of equation,

s=ut+\frac{1}{2}gt^{2}

Since the initial velocity and time is zero, then the time taken to reach the ground is stated as 0.8 s, so

   s=0+\left(\frac{1}{2} \times 9.8 \times 0.8 \times 0.8\right)=\frac{6.272}{2}=3.136 \mathrm{m}

So the distance covered by the acorn is 3.136 m.

8 0
3 years ago
A baseball of mass 300-g is hit at a velocity of 40 m/s. If the ball is caught by the third baseman and the ball penetrates 2.0
OlgaM077 [116]

The force is -12,000 N

Explanation:

First of all, we calculate the acceleration of the ball, by using the following suvat equation:

v^2-u^2=2as

where:

v = 0 is the final velocity of the baseball (it comes to rest)

u = 40 m/s is the initial velocity

a is the acceleration

s = 2.0 cm = 0.02 m is the displacement of the ball

Solving for a,

a=\frac{v^2-u^2}{2s}=\frac{0-40^2}{2(0.02)}=-40,000 m/s^2

Now we can calculate the average force exerted on the ball, by using Newton's second law:

F=ma

where

m = 300 g = 0.3 kg is the mass of the ball

a=-40,000 m/s^2 is the acceleration

Substituting,

F=(0.3)(-40,000)=-12,000 N

where the negative sign indicates that the direction of the force is opposite to the direction of motion of the ball.

Learn more about forces:

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

#LearnwithBrainly

8 0
3 years ago
How do you think density plays a role in the atmosphere?
Feliz [49]
Answer:
Also, gases like air are easily compressed. The weight of all the air above a given point in the atmosphere squeezes air molecules closer together. This causes the density to increase. The more air above a level (and hence the more weight of air above a level), the greater the compression.

Step By Step Explanation:
4 0
3 years ago
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