All categories

3 years ago

An atom’s emission of light with a specific amount of energy confirms that

Physics

2 answers:

tatiyna3 years ago

8 0

Answer:

the answer would be B :)

Explanation:

kirill [66]3 years ago

5 0

The correct answer is B. Electrons emit and absorb energy based on their position around the nucleus.

Explanation:

In general, an atom's emission of photons (light) is the result of electrons, which are the negative charge particles that orbit the nucleus. Moreover, the emission of light is likely to occur if the electron is located at a specific energy level (position in the atom) and it moves to a lower level as this requires the loss of energy in the form of photons. Also, the electron can absorb the photons and as a result gain enough energy to move to a higher level. This implies the atom's emissions of light shows the relationship between electrons emitting and absorbing energy and their position or energy level.

You might be interested in

Suppose you push a hockey puck of mass m across frictionless ice for a time \Delta t, starting from rest, giving thepuck speed v

bazaltina [42]

Answer:

1. $t_2 = 2t_1$

2. $t_2 = t_1\sqrt{2}$

Explanation:

1. According to Newton's law of motion, the puck motion is affected by the acceleration, which is generated by the push force F.

In Newton's 2nd law: F = ma

where m is the mass of the object and a is the resulted acceleration. So in the 2nd experiment, if we double the mass, a would be reduced by half.

$a_1 = 2a_2$

Since the puck start from rest, in the 1st experiment, to achieve speed of v it would take t time

$t = v / a_1$

Now that acceleration is halved:

$t = \frac{v}{2a_2}$

$\frac{v}{a_2} = 2t$

You would need to push for twice amount of time $t_2 = 2t_1$

2. The distance traveled by the puck is as the following equation:

$d = at^2$

So if the acceleration is halved while maintaining the same d:

$\frac{d_1}{d_2} = \frac{a_1t_1^2/2}{a_2t_2^2/2}$

As $d_1 = d_2$ , then $d_1/d_2 = 1$ . Also $a_1 = 2a_2$

$1 = \frac{2a_2t_1^2}{a_2t_2^2}$

$t_2^2 = 2t_1^2$

$t_2 = t_1\sqrt{2}\approx 1.14t_1$

So t increased by 1.14

7 0

3 years ago

What does the model below represent?

Viefleur [7K]

Answer:

Explanation:

Because we have two reactants and product

5 0

2 years ago

When you place leftover food in the refrigerator, what kind of energy do you

Verdich [7]

I believe the correct answer is D

8 0

3 years ago

Read 2 more answers

A manufacturer selected a metal to use in producing a lightweight button for clothing. A metal that has a density of 2.71 g/cm3

Natali5045456 [20]

Just find the density of every metal and select the one with a density of 2.71 g/cm³ . This is:

Metal 1

ρ = m/V

ρ = 22.1 g / 3 cm³

ρ = 7.367 g / cm³

Metal 2

ρ = m/V

ρ = 42 g / 4 cm³

ρ = 10.5 g / cm³

Metal 3

ρ = m/V

ρ = 9.32 g / 5 cm³

ρ = 1.864 g / cm³

Metal 4

ρ = m/V

ρ = 8.13 g / 3 cm³

ρ = 2.71 g / cm³

<h2>R / Metal 4 was selected.</h2>

4 0

3 years ago

A furlong is an old british unit of length equal to 0.125 mi, derived from the length of a furrow in an acre of ploughed land. a

castortr0y [4]

The speed of light is: c = 3x10^8 m/s <span>

or

c = 186,000,000 miles/sec = 1.86x10^8 mi/s

1 furlong = 0.125 mile

1 fortnight = 2 weeks(7d/wk)(24h/d)(3600s/h)
= 1209600s = 1.2096x10^6 s

Therefore,

c =1.86x10^8 mi/s(1furl/0.125mi)(1.2096x10^6s/fort)

<span>c = 18x10^14 furlong/fortnight = 18x10^8 Mfurlong/fortnight</span></span>

4 0

3 years ago