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olga_2 [115]
2 years ago
14

What is the maximum number of orbitalks for each set of quantum numbers? If it is not possible to determine the maximum number o

f orbitals, then please provide an explanantion.
a) n=4 l=2 ml=-2
b) n=7 l=5
c) n=5 l=1
d) n=3 l=0 ml=+1
Chemistry
1 answer:
kolbaska11 [484]2 years ago
8 0

Answer:

See Below for answer!

Explanation:

In order to find the number of orbitals given the principal quantum number, n, we can use 2n^{2}. For example n=2 would have 8 orbitals.

A) 32

B) 98

C) 50

D) 18

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Pls help. I have the question in a ss
gladu [14]

Answer:

D.

Explanation:

The hypothesis was that speed would increase with the addition of mass from passengers. The data shows that when passengers/mass are added, speed decreases.

4 0
3 years ago
Determine the pH of a 0.188 M NH 3 solution at 25°C. The K b of NH 3 is 1.76 × 10 -5.
Archy [21]

Answer:

pH is 8.52

Explanation:

According to the working in the photo

5 0
3 years ago
Determining Molar Mass
alisha [4.7K]

The molar mass of the following compounds in two decimal places are as follows:

  • NH3: 17.04 g/mol
  • Mg(OH)2: 58.33 g/mol
  • Fe2O3: 159.70 g/mol

<h3>MOLAR MASS:</h3>

The molar mass of a compound is the sum of all the atomic masses of the elements that constitutes the compound.

According to this question, three compounds were given as follows: NH3, Mg(OH)2 and Fe2O3.

The atomic mass of the elements in this compounds are as follows:

  • N = 14
  • H = 1
  • Mg = 24
  • O = 16
  • Fe = 56

  1. The molar mass of NH3 = 14 + 3 = 17g/mol
  2. The molar mass of Mg(OH)2 = 24 + 32 + 2 = 58g/mol
  3. The molar mass of Fe2O3 = 56(2) + 16(3) = 160g/mol

Learn more about molar mass at: brainly.com/question/12127540

6 0
2 years ago
Read 2 more answers
Determine the number of atoms in 51.0 grams of sodium, Na. (The mass of one mole of sodium is 22.99 g.)
miskamm [114]

Answer:

The answer is

<h3>1.340 × 10²⁴ sodium atoms</h3>

To find the number of atoms of sodium we use the formula

N = n × L

where

n is the number of moles

N is the number of entities

L is Avogadro's constant which is

6.02 \times  {10}^{23}

We need to find the number of moles first

The formula is

n =  \frac{m}{M}

where

M is the molar mass

m is the mass

n is the number of moles

From the question

M = 22.9 g/mol

m = 51.0 g

n =  \frac{51}{22.9}

n = 2.227 moles

So the number of sodium atoms is

N = 2.227 \times 6.02 \times  {10}^{23}

We have the final answer as

<h3>1.340 × 10²⁴ sodium atoms</h3>

Hope this helps you

3 0
3 years ago
Someone can help me with that?
noname [10]
For for the formulas with the abbreviated names of the ions, you switch the exponents for each one, so for number 2 it would be Fe2O3 or for 6 it would be CaCl2
For the compounds, you take the abbreviated names of the ions from the periodic table and wherever the ion falls, that’s how many electrons it has and so it would need more ions to make the full shell, so for sodium chloride, since both need one, it would be NaCl or for tin (ll) fluoride, it would be SnF2
3 0
3 years ago
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