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2 years ago

What's an atom ? Science

2 answers:

8 0

Answer: the basic units of matter and the defining structure of elements/Smallest part of an element that can still retain the properties of that element

Explanation:

makvit [3.9K]2 years ago

6 0

Answer:

Explanation:

an atom itself is made up of three tiny kinds of particles called subatomic particles:proton neutron and electron. it is a fundamental piece of matter. In a normal (neutral) atom the number of protons and the number of electrons are equal. Often, but not always, the number of neutrons is the same, too.

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If the vapor pressure of an aqueous solution containing 6.00 moles of a nonvolatile solute has a vapor pressure of 19.8 torr, an

Margaret [11]

Answer:

36.5 mol

Explanation:

The vapor pressure of a solution of a non volatile solute in water is given by Raoult´s law:

P H₂O = χ H₂O x P⁰ H₂O

where χ H₂O is the mole fraction of water in the solution and P⁰ H₂O

In the turn the mole fraction is given by

χ H₂O = mol H₂O / total # moles = mol H₂O /ntot

Thus

P H₂O = mole H₂O / n tot x P⁰ H₂0

now the mol of H₂O is equal n tot - 6 mol solute

Plugging the values given in the question and solving the resultant equation

19.8 torr = ( ntot - 6 ) x 23.7 torr / n tot

19.8 ntot = 23.7 ntot - 142.2

ntot = 36.5 ( rounded to 3 significant figures )

5 0

2 years ago

How many milliliters of 0.200 M FeCl3 are needed to react with an excess of Na2S to produce 0.345 g of Fe2S3 if the percent yiel

GuDViN [60]

Answer:

25.53mL of 0.200 M FeCl₃ are needed to produce 0.345g of Fe₂S₃

Explanation:

Based on the reaction of the problem, 1 mole of Fe₂S₃ is produced from 2 moles of FeCl₃.

0.345g of Fe₂S₃ are (Molar mass: 207.9g/mol):

0.345g of Fe₂S₃ ₓ (1 mol / 207.9g) = <em>1.6595x10⁻³ moles Fe₂S₃</em>

Moles of Fe needed to produce these moles of Fe₂S₃ are:

1.6595x10⁻³ moles Fe₂S₃ ₓ ( 2 moles FeCl₃ / 1 mole Fe₂S₃) =

<em>3.3189x10⁻³ moles of FeCl₃</em>

As the percent yield of the reaction is 65.0%, the moles of FeCl₃ you need to add are:

3.3189x10⁻³ moles of FeCl₃ ₓ (100.0% / 65.0%) = <em>5.106x10⁻³ moles of FeCl₃</em>

A solution 0.200M contains 0.200 moles per L. Volume to obtain 5.106x10⁻³ moles is:

<em>5.106x10⁻³ moles of FeCl₃ ₓ ( 1L / 0.200mol) = 0.02553L = </em>

<h3>25.53mL of 0.200 M FeCl₃ are needed to produce 0.345g of Fe₂S₃</h3>

8 0

2 years ago

The answer is what I need to know thank you

diamong [38]

Answer:250 and your matthew sister

8 0

2 years ago

The Ostwald process is used commercially to produce nitric acid, which is, in turn, used in many modern chemical processes. In t

const2013 [10]

Answer:

$\boxed{\text{47.4 g}}$

Explanation:

We are given the mass of two reactants, so this is a limiting reactant problem.

We know that we will need mases, moles, and molar masses, so, let's assemble all the data in one place, with molar masses above the formulas and masses below them.

M_r: 17.03 32.00 18.02

4NH₃ + 5O₂ ⟶ 4NO + 6H₂O

m/g: 70.1 70.1

Step 1. Calculate the moles of each reactant

$\text{Moles of CO } = \text{70.1 g} \times \dfrac{\text{1 mol}}{\text{17.03 g}} = \text{4.116 mol}\\\\\text{Moles of H$_{2}$O} = \text{70.1 g} \times \dfrac{\text{1 mol}}{\text{32.00 g}} = \text{2.191 mol}$

Step 2. Identify the limiting reactant

Calculate the moles of H₂O we can obtain from each reactant.

From NH₃:

The molar ratio of H₂O:NH₃ is 6:4.

$\text{Moles of H$_{2}$O} = \text{4.116 mol NH$_{3}$} \times \dfrac{\text{6 mol H$_{2}$O}}{\text{4 mol NH$_{3}$}} = \text{6.174 mol H$_{2}$O}$

From O₂:

The molar ratio of H₂O:O₂ is 6:5.

$\text{Moles of H$_{2}$O} = \text{2.191 mol O$_{2}$} \times \dfrac{\text{6 mol H$_{2}$O}}{\text{5 mol O$_{2}$}} = \text{2.629 mol H$_{2}$O}$

O₂ is the limiting reactant because it gives the smaller amount of H₂O.

Step 3. Calculate the theoretical yield.

$\text{Theor. yield } = \text{2.629 mol H$_{2}$O}\times \dfrac{\text{18.02 g H$_{2}$O}}{\text{1 mol H$_{2}$O}} = \textbf{47.4 g H$_{2}$O}\\\\\text{The maximum yield of H$_{2}$O is }\boxed{\textbf{47.4 g}}$

6 0

2 years ago

A common function of proteins and carbohydrates in the plasma membrane is...

Vika [28.1K]

I believe your answer is B.

8 0

3 years ago