What's an atom ? Science

2 answers:

8 0

Answer: the basic units of matter and the defining structure of elements/Smallest part of an element that can still retain the properties of that element

Explanation:

makvit [3.9K]3 years ago

6 0

Answer:

Explanation:

an atom itself is made up of three tiny kinds of particles called subatomic particles:proton neutron and electron. it is a fundamental piece of matter. In a normal (neutral) atom the number of protons and the number of electrons are equal. Often, but not always, the number of neutrons is the same, too.

You might be interested in

The volume of a gas is 450 mL when its pressure is 1.00 atm. If the temperature of the gas does not change, what is the

NikAS [45]

Answer: 0.225 atm

Explanation:

For this problem, we have to use Boyle's Law.

Boyle's Law: P₁V₁=P₂V₂

Since we are asked to find P₂, let's manipulate the equation.

P₂=(P₁V₁)/V₂

$P_{2} =\frac{(1.00atm)(0.45L)}{2.00L}$

With this equation, the liters cancel out and we will be left with atm.

P₂=0.225 atm

6 0

3 years ago

An electrochemical cell is composed of pure nickel and pure iron electrodes immersed in solutions of their divalent ions at room

Andrej [43]

Answer:

0.758 V.

Explanation:

Hello!

In this case, case when we include the effect of concentration on an electrochemical cell, we need to consider the Nerst equation at 25 °C:

$E=E\°-\frac{0.0591}{n} log(Q)$

Whereas n stands for the number of moles of transferred electrons and Q the reaction quotient relating the concentration of the oxidized species over the concentration of the reduced species. In such a way, we can write the undergoing half-reactions in the cell, considering the iron's one is reversed because it has the most positive standard potential so it tends to reduction:

$Fe^{2+}+2e^-\rightarrow Fe^0\ \ \ E\°=0.440V\\\\Ni^0\rightarrow Ni^{2+}+2e^-\ \ \ E\°=-0.250V$

It means that the concentration of the oxidized species is 0.002 M (that of nickel), that of the reduced species is 0.40 M and there are two moles of transferred electrons; therefore, the generated potential turns out:

$E=(0.440V+0.250V)-\frac{0.0591}{2} log(\frac{0.002M}{0.40M} )\\\\E=0.758V$