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1 year ago

Find the values of a and b that make the quadrilateral a parallelogram.

Mathematics

1 answer:

Yuri [45]1 year ago

5 0

Step-by-step explanation:

both halves of a diagonal must be equal.

so,

8b - 30 = 6b + 6

2b = 36

b = 18

and

9a - 13 = 5a + 5

4a = 18

a = 18/4 = 4.5

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If p(x) = 3x – 2and n (x) = 2x – 5, what is the value of (n/p) (1)?

Liula [17]

Answer:

-3

Step-by-step explanation:

We want (n/p)(1). We can obtain this by finding n(1) and p(1) and then dividing as indicated:

p(1) = 3(1) - 2 = 1

n(1) = 2(1) - 5 = -3

Then (n/p) (1) = -3/1, or just -3

5 0

2 years ago

Can someone pls help me with these equations

Zielflug [23.3K]

Answer:

1. y = -2x+5

2. y = 3/4 - 3

3. intercept = -5 slope = 4/3

4. intercept = 1 slope = -1/2

5 0

2 years ago

Is 8 one tenths of 80

Otrada [13]

Yeah 8 is 1/10th of 80.

6 0

3 years ago

Read 2 more answers

Pls give an explanation w your answer

Shalnov [3]

$a^{\frac{1}{n}}=\sqrt[n]{a}\\\\\left(a^n\right)^m=a^{n\cdot m}\\\\a^n\cdot a^m=a^{n+m}$
therefore
$64^\frac{1}{4}=\left(2^6\right)^\frac{1}{4}=2^{6\cdot\frac{1}{4}}\\\\=2^\frac{6}{4}=2^{1\frac{2}{4}}=2^{1+\frac{2}{4}}=2\cdot2^\frac{2}{4}\\\\=2\sqrt[4]{2^2}=2\sqrt[4]4$
Other method:
$64^\frac{1}{4}=\sqrt[4]{64}=\sqrt[4]{16\cdot4}=\sqrt[4]{16}\cdot\sqrt[4]4=2\sqrt[4]4$

4 0

2 years ago

Read 2 more answers

Please help!!!!

Solnce55 [7]

Answer:

c) ( $(6-\sqrt{12} )(6+\sqrt{12} ) = 24$