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shutvik [7]
3 years ago
14

Is 3√ a irrational number

Mathematics
1 answer:
umka2103 [35]3 years ago
4 0

Im going to assume that 3√ is √3

And √3 is irrational because You cant square root it without getting nuked with a Random Number generator of decimals.

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Mary walks from comer D to comer E to comer F on a city block that measures 264 feet wide and 900 feet long. Kate walks
Y_Kistochka [10]

Answer:

Difference between the distances traveled by Mary and Kate = 226 feet

Step-by-step explanation:

By applying Pythagoras theorem in right ΔDEF,

(DE)² + (EF)² = (DF)²

By substituting DE = 264 feet and EF = 900 feet

(264)² + (900)² = (DF)²

DF = √(69696+810000)

     = √879696

     = 937.92

Distance traveled by Kate diagonally = 938 feet

Distance traveled by Mary = DE + EF

                                            = 264 + 900

                                            = 1164 feet

Difference between the distances traveled by Mary and Kate = DF - (DE + EF)

= 1164 - 937.92

= 226.07

≈ 226 feet

3 0
2 years ago
Diego is building a kitchen table and a coffee table. The legs of a kitchen table must be twice the height of a coffee table and
muminat
The answer is B as the coefficient represents the number of legs
6 0
3 years ago
Read 2 more answers
Can someone help me for once ?​
hichkok12 [17]

Answer:

The answer is A)-4,6

Step-by-step explanation:

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6 0
2 years ago
Brainliest Answer! .....................................................
gayaneshka [121]
I think -16 that's what I think I hope it helps
4 0
3 years ago
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Find the area of the shaded region
Alex777 [14]

∆BOC is equilateral, since both OC and OB are radii of the circle with length 4 cm. Then the angle subtended by the minor arc BC has measure 60°. (Note that OA is also a radius.) AB is a diameter of the circle, so the arc AB subtends an angle measuring 180°. This means the minor arc AC measures 120°.

Since ∆BOC is equilateral, its area is √3/4 (4 cm)² = 4√3 cm². The area of the sector containing ∆BOC is 60/360 = 1/6 the total area of the circle, or π/6 (4 cm)² = 8π/3 cm². Then the area of the shaded segment adjacent to ∆BOC is (8π/3 - 4√3) cm².

∆AOC is isosceles, with vertex angle measuring 120°, so the other two angles measure (180° - 120°)/2 = 30°. Using trigonometry, we find

\sin(30^\circ) = \dfrac{h}{4\,\rm cm} \implies h= 2\,\rm cm

where h is the length of the altitude originating from vertex O, and so

\left(\dfrac b2\right)^2 + h^2 = (4\,\mathrm{cm})^2 \implies b = 4\sqrt3 \,\rm cm

where b is the length of the base AC. Hence the area of ∆AOC is 1/2 (2 cm) (4√3 cm) = 4√3 cm². The area of the sector containing ∆AOC is 120/360 = 1/3 of the total area of the circle, or π/3 (4 cm)² = 16π/3 cm². Then the area of the other shaded segment is (16π/3 - 4√3) cm².

So, the total area of the shaded region is

(8π/3 - 4√3) + (16π/3 - 4√3) = (8π - 8√3) cm²

7 0
2 years ago
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