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DENIUS [597]
2 years ago
6

How do you perform constructions related to circles? What theorems and explanations can be used to justify these constructions?

How do you perform constructions related to circles? What theorems and explanations can be used to justify these constructions?
Mathematics
1 answer:
Aleks [24]2 years ago
5 0

Answer and explanation:

To construct a circle, draw a line that represents the diameter of the circle. Bisect the line so that it is a perpendicular bisector of the diameter of the circle. Place your compass at the bisection point/midpoint and draw an arc or better still the whole circle.

Theorem: the perpendicular bisector of a chord passes through the center of a circle.

Note: a diameter of a circle is a chord that passes through the center of a circle.

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Arte-miy333 [17]
Two thirds can equal: 4/6, 6/9, 8/12, 10/15, etc.
7 0
2 years ago
This diagram is a straightedge and compass construction. A is the center of one circle,
zepelin [54]

ABC is a equilateral triangle .

Proof :-

Let's assume both circles as C1 and C2 [ as shown in the figure ]

  • AB is the radius of circle C1
  • AB is the radius of Circle C2

AC is the radius of circle C1.

BC is the radius of circle C2 .

AB and AC both are radius of circle C1 so both are equal ie AB = AC .

AB and BC both are radius of circle C 2 so both are equal ie AB = BC .

Hence we conclude that .

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6 0
2 years ago
Find the distance between the two points in simplest radical form.<br> (-5,0) and (-9,9)
Degger [83]

Answer:

√97 units

Step-by-step explanation:

the distance between the two points in (-5,0) and (-9,9) is √97 units.

3 0
2 years ago
Read 2 more answers
Is 50.2 a rational or an irrational number, why?
Greeley [361]

Answer:

Rational.

Step-by-step explanation:

\textbf{A rational number is a real number that can be expressed as}~ \dfrac{p}{q},\\\\\textbf{where}~ p~ \textbf{and}~ q~ \textbf{are integers.}\\\\ \boxed{50.2 = \dfrac{502}{10}}\\\\ \textbf{50.2 can be expressed as a ratio of two integers,}~ \textbf{so it is a rational number.}

4 0
2 years ago
Help me with this,i really forgot how to do these type of questions
Montano1993 [528]
Work=speed times time (my equation to help me figure it out)

ok, 10 men take 84 days to complete a job
therefor, each man completes 1/10 of the job in 84 days
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so, if we had 5 more, or 15 men

15 times 1/840 times xdays=1 job complete
15/840 times xdays=1job
times both sides by 840/15
xdays=840/15
xdays=56
56 days it would take
5 0
2 years ago
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