One affects radicle (root) growth while the other affects plumule shoot growth.
Its important because it tells us the difference between populations and individuals
Answer:
Dissolve 47.025 grams of sucrose in enough water to produce 250 ml of solution.
Explanation:
You need to prepare 250. mL of a 0.550 M aqueous solution of sucrose, C12H22O11 (aq),
which is used frequently in biological experiments.
Based on your answer above, what is the value of x?
Solution:
A 0.550 M aqueous solution contains 0.550 mole of sucrose per liter of solution.
250 ml = 0.250 liter
Thus a 0.250 liter of a 0.550 M aqueous solution of sucrose contains 0.250 * 0.550 = 0.1375 mole of sucrose
Recall:
Mass = number of moles * mass of 1 mole
mass of 1 mole of C12H22O11
= 12(12) + 1(22) + 16(11)
= 144 + 22 + 176
= 342 grams
Mass = 0.1375 * 342 = 47.025 grams of sucrose.
Dissolve 47.025 grams of sucrose in enough water to produce 250 ml of solution.
A Nuclear transfer is used for Creating Clones
Answer:
The correct answer is C. In the plaque assay for bacteriophages, the plaque is a clear zone caused by a zone of lysis.
Explanation:
The plaque assay is an approach used for titering bacteriophage stocks or determining the quantity of infectious virus in a sample. Plaques are visualized if you spot the phage on a lawn of growing compatible bacteria. Each plaque indicates an initial infection with one phage followed by lysis of neighboring bacteria in the lawn. Only viruses that cause visible damage of cells can be assayed in this way. The plaque assay is used to determine viral titer as plaque-forming units per ml so that known amounts of virus can be used to infect cells during subsequent work.
In the plaque assay for bacteriophages, the plaque is a clear zone caused by a zone of lysis.