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denis23 [38]
2 years ago
9

If the tension in the rope is 160 n, how much work does the rope do on the skier during a forward displacement of 270 m?

Physics
2 answers:
Lunna [17]2 years ago
8 0

If the tension in the rope is 160 n, - 43200 J work doen by the rope on the skier during a forward displacement of 270 m.

Given,

Tension force in the rope is (T) = 160 N

Displacement of the skier (S) = 270 m

The displacement takes place in forward direction while the direction of the tension in the rope is opposite to it.

Therefore, work done by the rope on  the skier is,

   W=T.S

⇒W=270*160*cos\pi \\W=-43200 J

Hence work done by the rope is - 43200 J.

Learn more about force problems on

brainly.com/question/26850893

#SPJ4

Mandarinka [93]2 years ago
6 0

The correct answer is - 43200 J.

If the tension in the rope is 160 n, - 43200 J work doen by the rope on the skier during a forward displacement of 270 m.

Given,

Tension force in the rope is (T) = 160 N

Displacement of the skier (S) = 270 m

The displacement takes place in forward direction while the direction of the tension in the rope is opposite to it.

Therefore, work done by the rope on  the skier is,⇒

Hence work done by the rope is - 43200 J.

What is work ?

Work is the energy transferred to or from an object by applying force along a displacement in physics. It is frequently represented as the product of force and displacement in its most basic form. When a force is applied, it is said to do positive work if it has a component in the direction of the point of application's displacement. If a force has a component that is opposite the direction of displacement at the force's application point, it does negative work.

To learn more about Work from the given link:

https://brainly.in/question/16349611

#SPJ4

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Two 0.2304 cm x 0.2304 cm square aluminum electrodes, spaced 0.5974 mm apart are connected to a 61 V battery. What is the charge
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Answer:

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Explanation:

for the distance between the plates d and given the area of plates, A, and ε = 8.85×10^-12 C^2/N.m^2, the capacitance of the plates is given by:

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   =[(0.2304×10^-2)(0.2304×10^-2)×(8.85×10^-12))/(0.5974×10^-3)

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