Question

• (-/1 Points) DETAILS OSCOLPHYS2016 9.5.WA.040.

Answer 1

The force that must be exerted on the outside wheel to lift the anchor at constant speed is 6.925 x 10⁵ N.

Force exerted outside the wheel

The force exerted on the outside of the wheel can be determined by applying the principle of conservation of angular momentum as shown below.

∑τ = 0

• Let the distance traveled by the load = 1.5 m
• Let the radius of the wheel or position of the force = 0.45 m

∑τ = R(mg) - r(F)

rF = R(mg)

0.45F = 1.5(21,200 x 9.8)

F = 6.925 x 10⁵ N.

Thus, the force that must be exerted on the outside wheel to lift the anchor at constant speed is 6.925 x 10⁵ N.

Learn more about angular momentum here: brainly.com/question/7538238